Answer:
Net force exerted on the radio is 27.5 Newton.
Given:
Mass = 5.5 kg
Acceleration = 5
To find:
Force exerted on the radio = ?
Formula used:
F = ma
Where F = net force
m = mass
a = acceleration
Solution:
According to Newton's second law of motion,
F = ma
Where F = net force
m = mass
a = acceleration
F = 5.5 × 5
F = 27.5 Newton
Hence, Net force exerted on the radio is 27.5 Newton.
Answer:
a) 32.58 m/s²
b) 161.84 m/s
Explanation:
Initial velocity = u = 0
Final velocity = v = 145 m/s
Time taken = t = 4.45 s
s = Displacement of dragster = 402 m
a = Acceleration
The final velocity is greater than the velocity used to find the average acceleration due to the gear changes. The first gear in a dragster has the most amount of toque which means the acceleration will be maximum. The final gears have less torque which means the acceleration is lower here. The final gears have less acceleration but can spin faster which makes the dragster able to reach higher speeds but slowly.
Answer:
The electric field due to the right ring at a location midway between the two rings is
Explanation:
Given that,
Radius of first ring = 5 cm
Radius of second ring = 20 cm
Charge on the left of the ring = +30 nC
Charge on the right of the ring = -30 nC
We need to calculate the electric field due to the right ring at a location midway between the two rings
Using formula of electric field
Put the value into the formula
Hence, The electric field due to the right ring at a location midway between the two rings is