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Andrews [41]
3 years ago
8

There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number. That s

mallest is 12,345 and the largest is 54,321. If these 120 numbers are listed in order from smallest to largest, what is the 73rd number in the list?
Mathematics
1 answer:
Harman [31]3 years ago
8 0

Answer:

41235

Step-by-step explanation:

There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number,

The total number of times where each number will occur or be at first place is calculated as:

4! = 4 × 3 × 2 × 1

= 24

Hence,

24th number = The last number where 1 is at first place

We can write this out as:

12345

12354

12435

12453

12534

12543

13245

13254

13425

13452

13524

13542 e.t.c.

48th number = The last number where 2 is at first place

72nd place = The last number where 3 is at first place.

This means, the 73rd number is the first number where 4 is at first place.

Therefore, the 73rd number based on pattern is 41235

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Answer:

<u>x = 36</u>

Here's how I got that:

<em>    - Group like terms -</em>

x - 2 + 2x + 4 + 2x - 2 = 180

                    ↓

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                    ↓

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<em>  - Divide both sides by 5 - </em>

<em>         </em>  5x/5 = 180/5

                   ↓

<em>                </em><u><em>x </em></u><u>= 36</u>

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<em>-Siascon</em>

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