Solve the inequality , find the max possible value for the variable.
3t + 1 < t + 12
2t < 11
t < 5.5
t_max = 5.5
For the second question just solve as two separate inequalities
4 +2 < x <= 7 + 2
6 <x <= 9
x in ]6, 9]
Answer:
42 tickets
Step-by-step explanation:
First winning = 90 tickets
Bonus won = 5 times the number of tickets of the original second prize
Total tickets won = 300
That is ;
First winning + bonus = 300 tickets
Let :
Number Tickets won by original second price = x
Bonus = 5x
Then;
90 + 5x = 300
5x = 300 - 90
5x = 210
x = 210 / 5
x = 42
A+5=6
Subtract 5 from both sides
A+5-5=6-5
A=1
Hope that helps
The correct answer is…… Yo Mum
Answer:
x= -5
Step-by-step explanation:
8+(-5)=3
