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3 years ago

In which phase change does a substance change from a liquid to a gas

Physics

2 answers:

Semmy [17]3 years ago

6 0

If it’s heated liquid will change into gas

matrenka [14]3 years ago

3 0

I believe the term you are looking for is evaporation. Let me know if this is wrong.

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The use of nuclear reactors to generate electricity is?

SVEN [57.7K]

The difference is that nuclear plants do not burn anything. Instead, they use uranium fuel, consisting of solid ceramic pellets, to produce electricity through a process called fission<span>. Nuclear power plants obtain the heat needed to produce steam through a physical process.

Hope this helps :)</span>

6 0

3 years ago

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How heavy is an object that displaces 400N of water in a pool?

julia-pushkina [17]

All we can say is that the object's volume is about 41 liters. That's the same as the volume of water displaced.

We can't say anything about the object's weight. There is no direct connection between the weight of the object and the weight of the water it displaces.

7 0

3 years ago

A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 N frictional force. He pushes in a dire

svp [43]

Answer:

(A). The work done on the cart by the friction is -700 J.

(B). The work done on the cart by the gravitational force is 0 J.

(C). The work done on the cart by the shopper is 700 J.

(D). The force the shopper exerts 38.61 N.

(E). The total work done on the cart is zero.

Explanation:

Given that,

Distance = 20.0 m

Frictional force = 35.0 N

Angle = 25.0°

(A). We need to calculate the work done on the cart by the friction

Using formula of work done

$W_{fr} = -F\cdot d$

Where, F = force

d = distance

Put the value into the formula

$W_{fr}=-35.0\times20$

$W_{fr}=−700\ J$

(B). The work done by the gravity is perpendicular to the direction of the motion

We need to calculate the work done on the cart by the gravitational force

Using formula of work done

$W=fd\cos\theta$

Put the value into the formula

$W=35.0\times20\cos90$

$W=0\ J$

(C). We need to calculate the work done on the cart by the shopper

Using formula of work done

$W_{sh}=W_{net}-W_{fr}$

Put the value into the formula

$W_{sh}=0-(-700)$

$W_{sh}=700\ J$

(D). We need to calculate the force the shopper exerts

Using formula of force

$F_{sh}=\dfrac{W_{fr}}{d\cos\theta}$

Put the value into the formula

$F_{sh}=\dfrac{700}{20\cos25}$

$F_{sh}=38.61\ N$

(E). We need to calculate the total work done on the cart

Using formula of work done

$W_{cart}=W_{fr}+W_{sh}$

Put the value into the formula

$W_{cart}=700-(-700)$

$W_{cart}=0\ J$

Hence, (A). The work done on the cart by the friction is -700 J.

(B). The work done on the cart by the gravitational force is 0 J.

(C). The work done on the cart by the shopper is 700 J.

(D). The force the shopper exerts 38.61 N.

(E). The total work done on the cart is zero.

6 0

3 years ago

A car of mass 1200 kg is traveling at 2 m/s. Then it collides with a heavy boulder in the road. During the collision, the car mo

olga2289 [7]

Answer:

F = 1.6*10⁴ N

Explanation:

Given distance x = 0.15m, mass m = 1200kg, velocity v = 2m/s.

Unknown: force F

Force is given by Newton's law:

(1) $F = ma$

The average force to stop an object from a velocity will be the same force necessary to accelerate an object from rest to the same velocity.

The distance for an object starting from rest for a constant acceleration is given by:

(2) $x=\frac{1}{2}at^2$

The velocity for an object starting from rest for a constant acceleration:

(3) $v=at$

Using equation 2 and 3 to eliminate time t:

(4) $x=\frac{1}{2}a\frac{v^2}{a^2}=\frac{v^2}{2a}$

Solving equation 4 for the acceleration a:

(5) $a=\frac{v^2}{2x}$

Using equation1 to solve for the force F:

(6) $F=ma=\frac{mv^2}{2x}$

4 0

4 years ago

If the current in a wire is 2.0 amperes and the potential difference across the wire is 10.0 volts, what is the resistance of th

avanturin [10]

Answer:

v=IR

10÷2 =R

R=5 Ohm

.. .

4 0

3 years ago

Read 2 more answers