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Dvinal [7]
3 years ago
15

A person notices a mild shock if the current along a path through the thumb and index finger exceeds 77 μA. Compare the maximum

possible voltage without shock across the thumb and index finger with a dry-skin resistance of 4.4 ✕ 105 Ω and a wet-skin resistance of 1,750 Ω.
Physics
1 answer:
Elenna [48]3 years ago
5 0

Answer:

Maximum possible voltage without shock across the thumb and index finger with a dry-skin = 33.88 V

Maximum possible voltage without shock across the thumb and index finger with a wet-skin = 0.135 V

Explanation:

From Ohm's law

V = IR

For the maximum possible voltage without shock for dry skin, the

R = 4.4 × 10⁵ Ω

I ≤ 77 μA

I ≤ 77 × 10⁻⁶ A

V ≤ 4.4 × 10⁵ × 77 × 10⁻⁶ = 33.88 V

For the maximum possible voltage without shock for dry skin, the

R = 1750 Ω

I ≤ 77 μA

I ≤ 77 × 10⁻⁶ A

V ≤ 1750 × 77 × 10⁻⁶ = 0.13475 V

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1.
Ivenika [448]

The ant's resultant velocity is 0.51 m/s at 78.7°

Since the ant is moving with a velocity of 0.1 m/s in the +x direction relative to the treadmill, and the treadmill is moving 0.5 m/s in the +y direction, the magnitude of the resultant velocity of the ant relative to the ground (since both directions are perpendicular) is thus

V = √(x² + y²)

= √[(0.1 m/s)² + (0.5 m/s)²]

= √[0.01 m²/s² + 0.25 m²/s²]

= √(0.26 m²/s²)

= 0.51 m/s.

The direction is Ф = tan⁻¹(y/x)

= tan⁻¹(0.5 m/s ÷ 0.1 m/s)

= tan⁻¹(5)

= 78.69°

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The ant's resultant velocity is 0.51 m/s at 78.7°

Learn more about resultant velocity here:

brainly.com/question/15093278

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