Why is the warm air rising while the cold air is sinking

2 answers:

7 0

Cold air is denser and heavier, whereas warm air has less density and is lighter. heavier mediums sink, and lighter mediums float.

UNO [17]3 years ago

6 0

Because cold air tends to more dense, and it's therefore heavier, and it sinks.
Hot air though is hot with no density so it's light and rises.

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A car is initially travelling at 12.1m/s It accelerates at a rate of -3.9m/s^2 for 7 seconds. What is it’s final velocity?

rosijanka [135]

It will be traveling in the reverse direction it was originally going at 15.2 m/s

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3 years ago

How is the rotation of the sun, different from the rotation of the earth

vesna_86 [32]

Answer:

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2 years ago

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Out of the given options, ‘it is described as a fundamental force and therefore does not depend on other forces’ is the true statement about gravity.

Answer: Option B

<u>Explanation: </u>

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Where,

G = Gravitational Constant

$m_{1} , m_{2}$ = Masses of two substances under consideration

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On a safety test course, a 1000 kg car heading north at 5 m/s collides head-on with an 800 kg car heading south at 4 m/s. At the

Luden [163]

Answer:

The speed is $3.5\frac{m}{s}$ and the direction is heading north.

Explanation:

In collisions the force exerted by the objects that collide is higher enough than the external forces that we can neglect that external forces, with that assumption we can use the conservation fo momentum law that states, final total momentum (pf) is equal initial total momentum (pi) if there’re not external forces or they are small enough to be neglected. Mathematically:

$p_f=p_i$

The total momentum is the sum of the momentum of each of the bodies we're dealing, in our case the moment of each car, then:

$p_{nf}+p_{sf}=p_{ni}+p_{si}$

with pn the momentum of the 1000kg car heading north and ps the 800kg car heading south. Momentum is defined as mass times velocity, then:

$m_nv_{nf}+m_sv_{sf}=m_nv_{ni}+m_sv_{si}$ (1)

It's important to note that when we talk about momentum and velocity direction matters, so we're are going to choose a system of reference where quantities pointing north are positive and pointing south are negative. So, the initial velocity of 1000 kg car is vni=5 m/s, initial velocity of 800 kg car is vsi=-4 m/s and the final velocity of 1000 kg car is vnf=-1 m/s. Now we can solve (1) for vsf and use the values we already have:

$v_{sf}=\frac{m_nv_{ni}+m_sv_{si}-m_nv_{nf}}{m_s}=\frac{(1000)(5)+(800)(-4)-(1000)(-1)}{800}$