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Citrus2011 [14]
2 years ago
11

Marcy pulls a backpack on wheels down the 100 m hall. The 60N force is applied at an angle of 30° above the horizontal. How much

work done on the weights? show full working out​
Physics
1 answer:
shutvik [7]2 years ago
6 0

Work= Fcos∆×S

W=60N×cos 30⁰×100

W=60×0.866×100=5196.1J

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While John is traveling along a straight interstate highway , he notices that the mile marker reads 248 km. John travels until h
sergiy2304 [10]

Answer:

I'm just going to tell you the information you need but not the answer so you can learn from the problem.

Explanation:

So he was at 248 km mark and traveled 99 km to get to the 149km mark. Then he turns around to go back 18 km to the 167 km mark. That is all the information you need to complete the question I recommend drawing it out in your notes.

3 0
3 years ago
Riders on a ferris wheel move in a circle with a speed of 4.0 m/s. As they go around, they
Vanyuwa [196]
Answer: D = 16m

Explanation: given values: a = 2 m/s2, v = 4 m/s
In this case we have to determine the diameter of the Ferris wheel.
Diameter of circle is given as: D = 2.r.
First we have to find radius of wheel. The best way to find that is using the centripetal acceleration equation: a = v2/r
Plug in values in above equation to find radius: 2 m/s2 = (4 m/s)2/r 2 m/s2 = (16 m2/s2)/r r = (16 m2/s2)/2 m/s2
r = 8.0m
Diameter of Ferris wheel is:
D = 2.r.
D = 2.8m
D = 16m
6 0
2 years ago
The force of repulsion between two like-charged particles will increase if
svlad2 [7]
If they're brought closer together
5 0
2 years ago
Read 2 more answers
(b) The cylinder shown in figure 2 is fitted with a freely sliding piston containing an ideal gas of mass 13g and volume 1.0×10⁴
nekit [7.7K]

Answer:

22600 cm³ (3 s.f.)

Explanation:

Please see the attached picture for the full solution.

6 0
2 years ago
HELP PLS i need this right now
N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }

where:

Vx = - 43 units

Vy = 11.1 units

Now replacing:

V=\sqrt{(-43)^{2} +(11.1)^{2} }\\V=44.4 units

7 0
3 years ago
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