Answer:
Thanks for asking!
Step-by-step explanation:
For ABD x equals 18 and for DBC equals 54.
8x3 is 24, 3x5 is 15, 8x5 is 40, 24 + 15 + 40 is 79 79x2 is 158
Answer:
6.32
Step-by-step explanation:
To find the side length on a right angled triangle we follow The Pythagorean Theorem:
![{a}^{2} + {b}^{2} = {c}^{2}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%20%3D%20%20%7Bc%7D%5E%7B2%7D)
c being the hypothesis (longest side: the hypotenuse is always opposite the right angle)
so..
![{6}^{2} + {2}^{2} = {x}^{2} \\ 36 + 4 = {x}^{2} \\ 40 = {x}^{2} \\ \sqrt{40} = \sqrt{ {x}^{2} } \\](https://tex.z-dn.net/?f=%20%7B6%7D%5E%7B2%7D%20%20%2B%20%20%20%7B2%7D%5E%7B2%7D%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%5C%5C%2036%20%2B%204%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%5C%5C%2040%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%5C%5C%20%20%5Csqrt%7B40%7D%20%20%20%3D%20%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20%5C%5C%20%20)
![6.32 = x](https://tex.z-dn.net/?f=6.32%20%3D%20x)
1) The lengths of the other 2 sides are 51 feet.
Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal
162 = 60 + 2x
x = the equal sides of the triangle.
162 - 60 = 102
102 = 2x
Divided by 2
51 = x
51 + 51 = 102. 102 + 60 = 162
2)
Pool 1: 311.38ft.
8*19.4 = 155.2
8 * 5.7 * 2 = 91.2
5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98
155.2 + 91.2 + 64.98 = 311.39
Pool 2: Either 863.94ft or 484 + 121πft
22 * 22 = 484
22/2 = 11, So, the radius of the half circle is 11
Circle area = (pi)r^2
11*11 = 121
pi * 121 = 121pi
Using 3.14 substitute: 3.14 * 121 = 379.94
379.94 + 484 = 863.94
Pool 3: 207ft
Rhombus area = pq/2
18 * 12 = 216
216/2 = 108
11 * 18 = 198/2 = 99
99 + 108 = 207