Write an equation in standard form of a quadratic function that has x-intercepts -2 and 5 and k=-4

Mathematics

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

-2x + 5 = -4k

Step-by-step explanation:

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given the two points (-24,7) and (30,25) a. What is an equation passing through the points? b. Is (51, 33) also on the same line

kicyunya [14]

Part 1) Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?

step 1
find the slope m
m=(y2-y1)/(x2-x1)---->m=(25-7)/(30+24)----> m=18/54----> m=1/3

step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15

the answer Part 1) is
y=(1/3)*x+15

Part 2) Is (51, 33) also on the same line?
if the point (51.33) is on the line y=(1/3)*x+15
then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
the point does not belong to the given line

the answer Part 2) is
the point does not belong to the given line

see the attached figure