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Lorico [155]
2 years ago
6

One number is six more than a second number. four times the first is 10 less than 6 times the second. Find the numbers.

Mathematics
1 answer:
zavuch27 [327]2 years ago
5 0

\sf{\bold{\blue{\underline{\underline{Given}}}}}

  • One number is six more than a second number.
  • four times the first is 10 less than 6 times the second.⠀⠀⠀⠀

\sf{\bold{\red{\underline{\underline{To\:Find}}}}}

  • Find the two numbers.⠀

\sf{\bold{\purple{\underline{\underline{Solution}}}}}

⠀⠀⠀⠀

In questions given,One number is six more than a second number.

if second number is a

first number is a+6.

and,

four times the first is 10 less than 6 times the second.

So,

4×(a+6)=6a-10

we have to solve this.

\bold{4\times (a+6)=6a-10   } 

\bold{4a+24=6a-10   } 

\bold{6a-4a=24+10   } 

\bold{2a=34   } 

\bold{ a=\dfrac{34}{2}  } 

\bold{ a=17  } 

we,get our second number =a=17.

So,

first number =a+6=17+6=23

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Bess [88]

a =  - 2

Step-by-step explanation:

1)  Subtract 8 from both sides.

- 3a = 14 - 8

2) Simplify 14 - 8 to 6.

- 3a = 6

3) Divide both sides by, -3.

a = -   \frac{6}{3}

4) Simplify 6/3 to 2.

a =  - 2

Therefor, the answer is, a = -2.

8 0
3 years ago
Cate and Elena were playing a card game. The stack of cards in the middle had 24 cards in it to begin with. Cate added 5 cards t
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Answer:

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Step-by-step explanation:

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3 years ago
Sequence of Transformation
weeeeeb [17]

Answer:

F (4, 2) G (2, 2) H (0, -4)

Step-by-step explanation:

8 0
3 years ago
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What is the answer to this problem 413 ÷ 19
andrew11 [14]
The answer is 21.73684211
3 0
3 years ago
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The midpoint of AB is M(-5,1). If the coordinates of A are (-4,-5), what are the coordinates of B?
Elenna [48]

<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).  

The coordinates of A are (-4,-5),  

We need to find the coordinates of B.

We know that, mid-point formula for two points A(x_{1}, y_{1}) and B (x_{1}, y_{2}) is given by

M\left(x_{3}, y_{3}\right)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, in our problem, \mathrm{x}_{3}=-5, \mathrm{y}_{3}=1, \mathrm{x}_{1}=-4 \text { and } \mathrm{y}_{1}=-5

Now, on substituting values in midpoint formula, we get

(-5,1)=\left(\frac{-4+x_{2}}{2}, \frac{-5+y_{2}}{2}\right)

On comparing, with the formula,

\frac{-4+x_{2}}{2}=-5 \text { and } \frac{-5+y_{2}}{2}=1

-4+\mathrm{x}_{2}=-10 \text { and }-5+\mathrm{y}_{2}=2

\mathrm{x}_{2}=-6 \text { and } \mathrm{y}_{2}=7

Hence, the coordinates of b are (-6, 7).

5 0
3 years ago
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