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Sedbober [7]
3 years ago
6

you just received a raise after working for your company for a year. your newly hourly wage is $12.50. if you are paid biweekly

and you work a normally 40 hour week, what is your base salary per pay period
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

12.5 x 40 = 500

500 x 2 = 1000

You get $1,000 every 2 weeks you're paid.

Hope this helped hon!

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earnstyle [38]
X/4 + 1 = -6 
x/4 = -6 -1 
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3 years ago
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What is 3pairs of numbers that have 5 as their greatest common factor
cupoosta [38]
10, 20 , 30, 45 has 5 as their greatest common factor

6 0
3 years ago
It took Fred 17 days to save $36.55. At that rate, how long would it take him to save $70.95?
Vlad1618 [11]

Answer:

Fred would take 33 days to save $ 70.95.

Step-by-step explanation:

The number of days (t) is directly proportional to the quantity of money saved (c), in monetary units, then we can calculate the time taken to save $ 70.95 by simple rule of three:

t = 17\,d\,\times \frac{\$\,70.95}{\$\,36.55}

t = 33\,d

Fred would take 33 days to save $ 70.95.

4 0
2 years ago
What is the correct way to write a mathematical problem?​
Zina [86]

Answer:

Label your answer appropriately; if the question asks for measured units, make sure to put appropriate units on the answer. If the question is a word problem, the answer should be in words. In general, write your homework as though you're trying to convince someone that you know what you're talking about.

Step-by-step explanation:

6 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
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