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3 years ago

8

What is the following product?

1 answer:

Brrunno [24]3 years ago

8 0

Answer:

$\boxed{6\sqrt{6} }$

Step-by-step explanation:

$\sqrt{12} \sqrt{18}$

Multiply square roots.

$\sqrt{12 \times 18}$

$\sqrt{216}$

Simplify square root.

$\sqrt{36} \sqrt{6}$

$6\sqrt{6}$

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Is y=17 a linear function

timofeeve [1]

Answer:

No.

Explanation:

The term linear function refers to two distinct but related notions. This is just one point.

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4 years ago

A pair of sunglasses has 2 lenses. Each lenses has a radius of 3.5 inches.

sineoko [7]

Answer:

76.93

Step-by-step explanation:

bc your formula is A=πrsquared so 3.14(π) ×3.5×3.5 bc when it's squared it's the number times itself93

so 3.14×3.5×3.5=38.456

38.456+38.456 because you need the area for both so I added the same number to it or you can multiply by 2 if you want

38.456+38.456=76.93

5 0

4 years ago

in 1999 there were 69063 physicians specializing in family practice in the united states and its possessions the number of male

Alecsey [184]

Answer:

18,887

Step-by-step explanation:

7 0

3 years ago

Which expression gives the unit length of the line segment with the endpoints (-12, 8) and (2, 8)

Mashcka [7]

They have the same y coordinate, 8, so all we need to figure out is the distance between -12 and 2 of this horizontal line.
to do this add 12 and 2, you should get 14.
now using this information, find the expression that is equal to 14.
|-12|+|2|=14
|-12|-|2|=10
|8|+|8|=16
|8|-|8|=0
as we can see, the first expression would be the correct one.

5 0

3 years ago

Read 2 more answers

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago