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zhuklara [117]
3 years ago
12

The given potentials are observed for a calomel electrode: E ° = 0.268 V and E ( saturated KCl ) = 0.241 V . Use this informatio

n to predict the value of E for a silver-silver chloride electrode saturated with KCl . For the silver-silver chloride electrode, E ∘ = 0.222 V .
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer: The E for Silver-silver Chloride electrode = 0.287 V

Explanation:

Silver/Silver Chloride (Ag/AgCl) with a value for E° that is actually +0.222 V or approximately 0.23 V has the actual potential of the half-cell prepared in this way as +0.197 V vs SHE, (Standard Hydrogen Electrode) which arises because in addition to KCl, there is the contribuion of AgCl to the chloride activity, which isn't exactly unity.

Therefore, the E for the Ag/AgCl electrode would approximately equal 0.287 V

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What is the final temperature, in degrees Celsius, of the gas in the bubble outside the volcano if the final volume of the bubbl
lawyer [7]

The question is incomplete, here is the complete question:

A 127 mL bubble of hot gases at 213°C and 1.89 atm is emitted from an active volcano.

What is the final temperature, in degrees Celsius, of the gas in the bubble outside the volcano if the final volume of the bubble is 136 mL and the pressure is 0.850 atm , if the amount of gas does not change?

<u>Answer:</u> The temperature of the gas is -40°C

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=1.89atm\\V_1=127mL\\T_1=213^oC=[213+273]K=484K\\P_2=0.850atm\\V_2=136mL\\T_2=?

Putting values in above equation, we get:

\frac{1.89atm\times 127mL}{484K}=\frac{0.850atm\times 136mL}{T_2}\\\\T_2=\frac{0.850\times 136\times 484}{1.89\times 127}=233K

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

T(K)=T(^oC)+273

233=T(^oC)+273\\\\T(^oC)=-40^oC

Hence, the temperature of the gas is -40°C

3 0
3 years ago
Which of the following elements has the largest atomic size? S, Ba, Po, Ca<br>​
prohojiy [21]

Answer:

Ba has the largest atom size

7 0
3 years ago
Read 2 more answers
Why are the temperatures on other objects in the solar system more extreme than the temperatures on the Earth?
musickatia [10]
Hello there!

It is just based on the fact that they are closer or further away from the Sun.

Hope This Helps You!
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7 0
4 years ago
What is The pH and pOH of a 1.00x10-3M solution of CH3COOH (Ka=1.75x10-5) ?
zaharov [31]

Answer:

<h2>pH = 3.9</h2><h2>pOH = 10.1</h2>

Explanation:

Since CH _ 3COOH is a weak acid to find the pH of CH _ 3COOH we use the formula

pH =  -  \frac{1}{2}   log(Ka)  -  \frac{1}{2}  log(c)

where

Ka is the acid dissociation constant

c is the concentration

From the question

Ka of CH _ 3COOH = 1.75 × 10^-5

c = 1.00 × 10-³M

Substitute the values into the above formula and solve for the pH

That's

pH =  \frac{1}{2} ( -  log(1.75 \times {10 }^{ - 5} -  log(1.00 \times  {10}^{ - 3} )  )  \\   =  \frac{1}{2} (4.757  + 3) \\  =  \frac{1}{2}  \times 7.757) \\  = 3.8785 \:  \:  \:  \:  \:  \:  \:  \:

We have the answer as

<h3>pH = 3.9</h3>

To find the pOH we use the formula

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 3.9

We have the answer as

<h3>pOH = 10.1</h3>

Hope this helps you

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3 years ago
9, What is an Independent
stepan [7]

Answer:

Not influenced or controlled by others in matters of opinion

8 0
3 years ago
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