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zhuklara [117]
3 years ago
12

The given potentials are observed for a calomel electrode: E ° = 0.268 V and E ( saturated KCl ) = 0.241 V . Use this informatio

n to predict the value of E for a silver-silver chloride electrode saturated with KCl . For the silver-silver chloride electrode, E ∘ = 0.222 V .
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer: The E for Silver-silver Chloride electrode = 0.287 V

Explanation:

Silver/Silver Chloride (Ag/AgCl) with a value for E° that is actually +0.222 V or approximately 0.23 V has the actual potential of the half-cell prepared in this way as +0.197 V vs SHE, (Standard Hydrogen Electrode) which arises because in addition to KCl, there is the contribuion of AgCl to the chloride activity, which isn't exactly unity.

Therefore, the E for the Ag/AgCl electrode would approximately equal 0.287 V

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The focal length of the mirror can be obtained as follow:

\frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\\\\frac{1}{f} = \frac{1}{30} + \frac{1}{30}\\\\\frac{1}{f} = \frac{2}{30} \\\\\frac{1}{f} = \frac{1}{15} \\\\

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Therefore, the focal length of the mirror is 15 cm

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