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Ronch [10]
3 years ago
7

Jamal is working with three ionic compounds: sodium chloride, calcium sulfide, and barium oxide. His teacher asks him which are

the positive ions in each compound. What should Jamal’s answer be? sodium, calcium, and barium barium, sulfur, and oxygen calcium, barium, and chlorine chlorine, sulfur, and oxygen
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

option A is correct  ( sodium, calcium and barium)

Explanation:

Given compounds:

Sodium chloride , calcium sulfide, barium oxide

We know that metals form positive ions. In order to solve the problem we must identify the metals from given compounds.

Na⁺Cl⁻

Ca²⁺S²⁻

Ba²⁺O²⁻

We can see that sodium, calcium and barium contain positive charges.

Thus option A is correct.

Because sodium have one valance electron. When it combine with chlorine sodium lose its one electron to complete the octet and chlorine accept it to complete its octet. Thus sodium form positive ion and chlorine form negative ion.

Similarly barium and calcium are present in group 2. Both have two valance electron. When they lose them cation are formed.

Other option are incorrect because,

Option B have sulfur and oxygen which are anion.

Option C have chlorine which is also anion

Option D have chlorine, sulfur and oxygen that are anions.

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Answer:

23.71J is the work that the gas do.

Explanation:

The work that a gas do under isobaric conditions follows the formula:

W = P*ΔV

<em>Where W is work in atmL, P is the pressure and ΔV is final volume -Initial volume In Liters</em>

Replacing with the values of the problem:

W = P*ΔV

W = 0.600atm*(0.44000L - 0.0500L)

W = 0.234atmL

In Joules (1atmL = 101.325J):

0.234atmL × (101.325J / 1 atmL) =

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List 2 underlying causes of water pollution
olga_2 [115]

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industrialization and rapid human population growth.

Explanation:

Hope this helps

6 0
2 years ago
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The vapor pressure of water at 25.0°C is 23.8 torr. Determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
mrs_skeptik [129]

According to Raoult's law the relative lowering of vapour pressure of a solution made by dissolving non volatile solute is equal to the mole fraction of the non volatile solute dissolved.

the relative lowering of vapour pressure is the ratio of lowering of vapour pressure and vapour pressure of pure solvent

\frac{p^{0-}p}{p^{0}}=x_{B}

Where

xB = mole fraction of solute=?

p^{0}=23.8torr

p = 22.8 torr

x_{B}=\frac{23.8-22.8}{23.8}=0.042

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putting the values

molefraction=\frac{molessolute}{molesolute+molessolvent}

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zmey [24]

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Explanation:

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(b) The reactants are the same substance as the products. (wrong)

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