Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where 
and 
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
So, the fraction of races that he won was:
: you need ti divide the number of occurrences by the number of possibilities.
We can simplify this:
.
When we write it in decimals until the closest place, it's:
0.167 or 16.667%
- The IQR for the males' data is 25.
- The difference between the median of the males' data and the female's data is 14.
- The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
- A reason for the outlier is that the number of dogs needing care increased.
<h3>What is the interquartile range?</h3>
The interquartile range for the males data is the difference between the third quartile and the first quartile.
IQR = third quartile - first quartile
25 - 0 = 25
Median = 20 - 6 = 14
An outlier is a number that is way smaller or way larger than that of other numbers in a data set.
To learn more about outliers, please check: brainly.com/question/27197311
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C is the answer hope that helps have a good day
Answer:
when i got the answer i got 12a^25
Step-by-step explanation:
i dont know if this helps
