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3 years ago

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Bridge math sem 1 .! Need helpp.!!

1 answer:

Ray Of Light [21]3 years ago

8 0

The answer should be C

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Area is 96 length is 4x+8 width is x find x

dimulka [17.4K]

Answer

Step-by-step explanation:

The area would be length times width. x(4x+8) =96

4x^2+8x = 96

4x^2+8x-96=0. We need to factor.

It would be factored to (4x-16)(x+6) = 0

x would be -6 (x+6=0)

or x would be 4 (4x-16=0)

Why would the width be negative?!? So the answer is 4

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3 years ago

What is the circumference of a circle with diameter 7 units?

Aliun [14]

Answer:

C = 7pi units or approximately 21.98 units

Step-by-step explanation:

The circumference is given by

C = pi * d

We are given the diameter of 7

C = 7pi

We can approximate pi by 3.14

C = 7 *3.14

C =21.98 units

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4 years ago

How to solve a quadratic formula

Deffense [45]

Well the quadratic formula is just:
x = -b + and - the square root of b^2 - 4ac all divided by 2a. You just plug in numbers and get an answer for x.

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3 years ago

64% of 25 students in the class have a phone. How many students have a phone?

Damm [24]

Answer: 16

Step-by-step explanation: looked it up on Google

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3 years ago

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PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all

Xelga [282]

Answer:

1. $(A,B) = (3,-2)$

2. The values of t are: -3, -1

Step-by-step explanation:

Given

$\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

$|t| = 2t + 3$

Required

Solve for the unknown

Solving $\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

Take LCM

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}$

Expand the denominator

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}$

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}$

Both denominators are equal; So, they can cancel out

$x + 7 = A(x+1) + B(x-2)$

Expand the expression on the right hand side

$x + 7 = Ax + A + Bx - 2B$

Collect and Group Like Terms

$x + 7 = (Ax + Bx) + (A - 2B)$

$x + 7 = (A + B)x + (A - 2B)$

By Direct comparison of the left hand side with the right hand side

$(A + B)x = x$

$A - 2B = 7$

Divide both sides by x in $(A + B)x = x$

$A + B = 1$

Make A the subject of formula

$A = 1 - B$

Substitute 1 - B for A in $A - 2B = 7$

$1 - B - 2B = 7$

$1 - 3B = 7$

Subtract 1 from both sides

$1 - 1 - 3B = 7 - 1$

$-3B = 6$

Divide both sides by -3

$B = -2$

Substitute -2 for B in $A = 1 - B$

$A = 1 - (-2)$

$A = 1 + 2$

$A = 3$

Hence;

$(A,B) = (3,-2)$

Solving $|t| = 2t + 3$

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

$t = 2t + 3$ and $-t = 2t + 3$

Solving $t = 2t + 3$

Make t the subject of formula

$t - 2t = 3$

$-t = 3$

Multiply both sides by -1

$t = -3$

Solving $-t = 2t + 3$

Make t the subject of formula

$-t - 2t = 3$

$-3t = 3$

Divide both sides by -3

$t = -1$

<em>Hence, the values of t are: -3, -1</em>

7 0

3 years ago

Read 2 more answers