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Alexxandr [17]
3 years ago
11

Bridge math sem 1 .! Need helpp.!!

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0
The answer should be C
You might be interested in
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
BRAINLIEST
Cloud [144]

10 ways I think if its wrong I'm sorry

3 0
3 years ago
QuizBIGPOINT
lianna [129]

The number of permutations of the problem is

  1. This = 24
  2. Outfit = 360

<u>。。。。。。。。。。。。。。。。。。。。。。。。。。。。。</u>

<u>\:</u>

<h2>Combination</h2>

\:

Combinations are the number of ways to choose members from a certain number, namely from members of a set, combinations can also be interpreted as many ways to make subsets, namely with a certain number of members, namely from members of a set, if a set has n members then the selection of r members, and the combination of n is where r is less than n.

\:

<h3>The Formula : </h3>

\:

<h2>\frac {n!}{k! (n-k)!}</h2>

\:

<h2>Permutation</h2>

\:

Permutations are a way to determine the number of arrangements that occur by paying attention to the order. So in permutations, position/order is very important, namely AB is considered different from BA (AB ≠ BA). Permutation formula

\:

<h3>The Formula :</h3>

\:

\frac {n!}{k!} (With Double Elements)

n! (Without Double Elements)

\:

<h2>Factorial</h2>

\:

The factorial of a natural number is the successive multiplication of a natural number that begins with the number one and arrives at the natural number, the factorial is used in calculating combinations, probabilities, and permutations.

\:

<h3>For example</h3>

\:

  • 》2! = 1 × 2
  • 》3! = 1 x 2 x 3
  • 》4! = 1 x 2 x 3 x 4
  • 》5! = 1 x 2 x 3 x 4 x 5
  • 》6! = 1 × 2 × 3 × 4 × 5 × 6
  • 》7! = 1 × 2 × 3 × 4 × 5 × 6 × 7
  • 》8! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8
  • 》9! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9
  • 》10! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 10

\:

The following is an example of a factorial that does not involve mixed arithmetic operations, so if you want to add it up we just need to calculate it like a normal number, a factorial number that only multiplies the difference between a factorial number that is added up by addition, subtraction, multiplication, division, for example see below.

\:

6! x2! - 3! : 4!

\:

The example above is a mixed arithmetic operation that contains multiplication, subtraction, and division. Remember that in mixed arithmetic operations, multiplication/division must be completed before addition/subtraction.

\:

<h3>The Formula : </h3>

\:

n! (Combined Multiplication)

\:

<h2>Place Filling Rules</h2>

\:

The Place Fill Rule is a method or method that can be used to determine the number of ways an object occupies its place. The filling slots rule is a method of calculating how many possible ways there are in an experiment or event. If a first event can be done in m different ways and the second event can be done in a different way and so on until the last event in k.

\:

<h3>The formula</h3>

\:

n1 × n2 × n3 × ... × nr

\:

<u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u><u>。</u>

<h2><u>Question</u></h2>

Find the number of permutations of letters of the word

- this

- outfit

\:

<h2><u>Answer</u></h2>

"Number One"

=》This = Four Letters ( 4! )

P = 4!

P = 1 × 2 × 3 × 4

P = 2 × 3 × 4

P = 6 × 4

P = 24

==========

"Number Two"

=》Outfit = Six Letters ( 6! )

=》Outfit = Two Letters The Same ( "T" ) = 2!

P = \frac {1×2×3×4×5×6}{2×1}

P = \frac {2×3×4×5×6}{2}

P = \frac {6×4×5×6}{2}

P = \frac {24×5×6}{2}

P = \frac {120×6}{2}

P = \frac {720}{2}

P = 360

\:

<h2><u>Conclusion</u></h2>

So, the number of permutations of the problem is

  1. This = 24
  2. Outfit = 360

\:

<u>。。。。。。。。。。。。。。。。。。。。。。。。。。。。。</u>

<h2>Learn More</h2>

\:

  1. ➽ brainly.com/question/24659851
  2. ➽ brainly.com/question/14767366
  3. ➽ brainly.com/question/1216161

\:

<h2>Answer Detail</h2>

\:

  • ➽ Subject: Mathematics
  • ➽ Class : 12
  • ➽ Chapter : 7 - The Rule of Counting:
  • ➽ Maple Code
  • ➽ Categorization code : 12.2.7
  • ➽ Keywords : This, Outfit

5 0
3 years ago
PLEASE HELP i’m desperate
gulaghasi [49]

Answer:

id : 237 514 2470

pwd : frmCV5

4 0
3 years ago
Copy these incomplete number lines. Label the missing numbers on each of them.
Alexeev081 [22]

a.

20/2 = 10

0, 10, 20, 30, 40, 50

b.

32.4/4 = 8.1

0, 8.1, 16.2, 24.3, 32.4, 40.5

c.

8.8/4 = 2.2

0, 2.2, 4.4, 6.6, 8.8, 11

d.

10/3 = 3.3

0, 3.3, 6.7, 10, 13.3, 16.7

3 0
4 years ago
Read 2 more answers
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