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max2010maxim [7]
2 years ago
12

In a certain​ country, the life expectancy for women in 1900 was 4949 years and in 2000 it was 8181 years. Assuming that life ex

pectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and​ 2000, what will the life expectancy be for women in​ 2100?
Mathematics
1 answer:
Phantasy [73]2 years ago
4 0

Answer:

The life expectancy for 2100 will be 134 years.

Step-by-step explanation:

Consider the provided information.

In 1900 women life expectancy was 49 years and in 2000 it was 81 years.

First calculate the difference of life expectancy between 1900 to 2000.

81-49=32 years

Percentage change is:

\text{Percentage change}=\frac{32}{49}\times 100\approx65.31

It is given that the increase in percentage remains same.

Therefore, next year life expectancy will be:

\begin{aligned}81+65.31\% \times81&=81(1+\frac{65.31}{100})\\&=81(1.6531)\\&=133.9011\approx134\end{aligned}

Hence, the life expectancy for 2100 will be 134 years.

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Rationalize the denominator of the fraction: √5/√8 - √3
Lana71 [14]

Answer:

Step-by-step explanation:

Remark

The editor must have brackets put around the denominator when there are 2 terms.

That means I think the question is (√5) / (√8 - √3). If this is incorrect, leave a note.

To rationalize the denominator, you must multiply numerator and denominator by the conjugate  (√8 + √3).

Solution

√5 *  (√8 - √3) /  ( (√8 - √3) *  (√8 + √3)  )  

I don't think there is any point in removing the brackets in the numerator. Just leave it.

The denominator is a different matter.

denominator = ( (√8 - √3) *  (√8 + √3)  )

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6 0
2 years ago
6) Add or subtract:<br> a) (4x® - 5x + 15) - (11 - 7x - 2x)<br> b)(9x- 6x® - 7x-2) + (10x - 8x + 11)
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