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max2010maxim [7]
3 years ago
12

In a certain​ country, the life expectancy for women in 1900 was 4949 years and in 2000 it was 8181 years. Assuming that life ex

pectancy between 2000 and 2100 increases by the same percentage as it did between 1900 and​ 2000, what will the life expectancy be for women in​ 2100?
Mathematics
1 answer:
Phantasy [73]3 years ago
4 0

Answer:

The life expectancy for 2100 will be 134 years.

Step-by-step explanation:

Consider the provided information.

In 1900 women life expectancy was 49 years and in 2000 it was 81 years.

First calculate the difference of life expectancy between 1900 to 2000.

81-49=32 years

Percentage change is:

\text{Percentage change}=\frac{32}{49}\times 100\approx65.31

It is given that the increase in percentage remains same.

Therefore, next year life expectancy will be:

\begin{aligned}81+65.31\% \times81&=81(1+\frac{65.31}{100})\\&=81(1.6531)\\&=133.9011\approx134\end{aligned}

Hence, the life expectancy for 2100 will be 134 years.

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Let the missing length be represented as x.

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Step-by-step explanation:

The equations 8x + 4y = 32 and 16x + 12y = 72 represent the cost of lunch and dinner for a family in which x is the number of adults and y is the number of children.

We have to find the number of adults or the value of x by solving these equations.

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