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olya-2409 [2.1K]
3 years ago
10

HELP!!Find the eighth term of the sequence given by the rule

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

When you plug in 8 for n you get -14

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Set X: {51,49,37,28,33,39,49,42} <br><br> Set Y :{23,2934,36,39,22,25,33}
SpyIntel [72]

Answer:

X

Step-by-step explanation:

126

8 0
3 years ago
Solve by taking the square root I need help understanding steps this is hard for me. ​
Shalnov [3]

Answer:

x= -2 \pm \sqrt{13}

Step-by-step explanation:

Given: 3x^{2} -12x+27= 0

This is a quadratic equation.

3x^{2} -12x+27= 0

Taking common 3 from the equation given

⇒ 3(x^{2} -4x+9)=0

dividing both side by 3

⇒ x^{2} -4x+9=0

By using different factor, we can observe this trinomial can not be factored.

∴ solving it by completing the square.

⇒ x^{2} -4x+9=0

adding 9 on both side

⇒ x^{2} -4x= 9

To get a perfect square number as coeffecient of x is 4, lets add both side by 4.

⇒x^{2} -4x+4= 13

we know, (x+2)^{2} = x^{2} +2\times x\times 2+2^{2}

∴ (x+2)^{2} =13

Taking Square root on both side, remember; √a²= a

⇒ (x+2)= \sqrt{13}

opening parenthesis

⇒ x+2= \sqrt{13}

subtracting both side by 2

∴ x= -2 \pm \sqrt{13}

7 0
3 years ago
A car travels 2 5/8 miles in 3 1/2 minutes at a constant speed. How far did the car travel in 5 minutes?
ad-work [718]

Answer:

3.75 as a decimal

Step-by-step explanation:

6 0
3 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
3 years ago
I need help with this question ​
emmainna [20.7K]

Answer:

36-4-2x, she will have 8 rolls of toilet paper left over

Step-by-step explanation:

36=total-4= the four given away,2x= the number of rolls used per month. 36-4=32. 2(12) 1 year]= 24. 32-24=8

7 0
3 years ago
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