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3 years ago

A wave With wavelength 20 m has a frequency of 12 Hz what is the waves speed

Physics

1 answer:

pentagon [3]3 years ago

7 0

Answer:

240m/s

Explanation:

The equation to calculate is wavelength= velocity/ frequency so to find the velocity you would have to multiply frequency by wavelength.

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The length of a simple pendulum is 0.81 mand the mass of the particle (the "bob") at the end of the cable is0.23 kg. The pendulu

Gemiola [76]

Answer:

$\displaystyle w=3.478\ rad/sec$

$M=0.0182\ J$

$v=0.398\ m/s$

Explanation:

Simple Pendulum

It's a simple device constructed with a mass (bob) tied to the end of an inextensible rope of length L and let swing back and forth at small angles. The movement is referred to as Simple Harmonic Motion (SHM).

(a) The angular frequency of the motion is computed as

$\displaystyle w=\sqrt{\frac{g}{L}}$

We have the length of the pendulum is L=0.81 meters, then we have

$\displaystyle w=\sqrt{\frac{9.8}{0.81}}$

$\displaystyle w=3.478\ rad/sec$

(b) The total mechanical energy is computed as the sum of the kinetic energy K and the potential energy U. At its highest point, the kinetic energy is zero, so the mechanical energy is pure potential energy, which is computed as

$U=mgh$

where h is measured to the reference level (the lowest point). Please check the figure below, to see the desired height is denoted as Y. We know that

$H+Y=L$

And

$H=L\ cos\alpha$

Solving for Y

$Y=L(1-cos\alpha )$

$Since\ \alpha=8.1^o, L=0.81\ m$

$Y=0.0081\ m$

The potential energy is

$U=mgh=0.23\ kg(9.8\ m/s^2)(0.0081\ m)$

$U=0.0182\ J$

The mechanical energy is, then

$M=K+U=0+U=U$

$M=0.0182\ J$

(c) The maximum speed is achieved when it passes through the lowest point (the reference for h=0), so the mechanical energy becomes all kinetic energy (K). We know

$\displaystyle K=\frac{mv^2}{2}$

Equating to the mechanical energy of the system (M)

$\displaystyle \frac{mv^2}{2}=0.0182$

Solving for v

$\displaystyle v=\sqrt{\frac{(2)(0.0182)}{0.23}}$

$v=0.398\ m/s$

4 0

3 years ago

Rocks are elastic too! Explain how elasticity and Harry Reid's elastic rebound theory lead to a better understanding of earthqua

ANEK [815]

After the great 1906 San Francisco earthquake, geolophysicistHarry Fielding Reid examined the displacement of the ground surface along the San Andreas Fault. He concluded that the quake must have been the result of the elastic reboundof the strain energy in the rocks on either side of the fault.
strain energy is 0. 5x force x (compression) X (compression)
There is a lot of force and a bit of compression when rocks squash up against other rocks causing earthquakes

7 0

3 years ago

According to Newton's 2nd Law of Motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is

Mkey [24]

According to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a moving body can be calculated by dividing the force of the body by its mass.

According to this question, the mass of an object is 10 kg and the force is 10 newtons, then the acceleration can be calculated as follows:

acceleration = 10N ÷ 10kg

acceleration = 1m/s²

Therefore, according to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².

Learn more about acceleration at: brainly.com/question/12550364

#SPJ1

8 0

2 years ago

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr

Mandarinka [93]

Answer:

The magnitude of minimum potential difference is 1800 V

Explanation:

Given:

Electric field $E = 3 \times 10^{6} \frac{V}{m}$

Gap between electrodes $d = 0.060 \times 10^{-2}$ m

For finding the minimum potential difference,

$\Delta V = E \times d$

$\Delta V = 3 \times 10^{6} \times 0.060 \times 10^{-2}$

$\Delta V = 1800$ V

Therefore, the magnitude of minimum potential difference is 1800 V

8 0

3 years ago

Based on the data Thomson collected in his experiments using cathode rays, the concept of atomic structure was modified. What st

zzz [600]

I encountered this same question, these were the choices given.
1). In the atom, the particles of the cathode rays are embedded in a diffuse cloud of positive charge.
2).Cathode rays have mass. 
3).Matter contains positive and negative charge. 
4).The positive component of matter is also particulate in nature. 
5).Particles of the cathode rays are fundamental to all matter. 
6).An atom is divisible. 
7).Particles of the cathode rays are negatively charge.

There are more than one correct statement. These statements are:

2).Cathode rays have mass.
3).Matter contains positive and negative charge.
5).Particles of the cathode rays are fundamental to all matter. 6).An atom is divisible.

4 0

3 years ago