Answer:
F = 2,894 N
Explanation:
For this exercise let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
Angular and linear variables are related.
v = w r
Let's replace
F = m w² r
The radius r and the length of the rope is related
cos is = r / L
r = L cos tea
Let's replace
F = m w² L cos θ
Let's reduce the magnitudes to the SI system
m = 101.7 g (1 kg / 1000g) = 0.1017 kg
θ = 5 rev (2π rad / rev) = 31,416 rad
w = θ / t
w = 31.416 / 5.1
w = 6.16 rad / s
F = 0.1017 6.16² 0.75 cos θ
F = 2,894 cos θ
The maximum value of F is for θ equal to zero
F = 2,894 N
Answer:
below
Explanation:
Net accelerating force becomes 12-8 = 4 N
F = ma
4 = 2 * a
a = 2 m/s^2
Answer:
B. 59 kg
Explanation:
From the graph you notice that a linear relation in indicated by the line joining the points such that the points on the line represent the data that show a correct relationship in the experiment.
This means that the point outside the line has an error .
This point is the value 59 kg that does not align with other values which are included in the graph.
The formula for the density of a substance expressed in mass and volume is rho = mass/volume or p = m/v. Rearranging the formula to isolate volume gives the formula v = m/p. To solve for the problem given, this formula must be used. This gives a solution of:
v = m/p = 250 g/ 968 g/cm^3 = 0.258 cm^3 of sodium
Answer:
Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:
The purpose here is derive x(t) twice as follows:
Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.
