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melisa1 [442]
3 years ago
15

A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2

.5m on the floor. calculate the coefficient of sliding friction [g = 10.0 ms per second per second]
Physics
1 answer:
erastova [34]3 years ago
5 0
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




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Which action might lead scientists to develop new explanations about the
sweet [91]

Answer:

The correct option is;

B. Designing experiments to replicate the conditions in which life may have first evolved on Earth

Explanation:

The proof to the hypothesis that life originated from inanimate inorganic, or non-living  molecules which is an explanation for the origin of life on Earth was provided by an experiment designed and performed in 1953 by Stanley L. Miller and Harold C. Urey which consisted of using chemicals proposed in the hypothesis and combining them through a specific design process to replicate expected atmospheric condition before the life began on Earth.

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3 years ago
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What can be known about the density of sodium
lesya692 [45]
D? maybe i’m trying to. see if it’s d or b
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3 years ago
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A 25-kg child sits at the top of a 4-meter slide. After sliding down, the child is traveling at 5 m/s. How much PE does he start
Semmy [17]

Daniddmelo says it right there, don't know why he got reported.

The potential energy (PE) is mass x height x gravity. So it would be 25 kg x 4  m x 9.8 = 980 joules. The child starts out with 980 joules of potential energy. The kinetic energy (KE) is (1/2) x mass x velocity squared. KE = (1/2) x 25 kg x 5 m/s2 = 312.5 joules. So he ends with 312.5 joules of kinetic energy. The Energy lost to friction =  PE - KE. 980- 312.5 = 667.5 joules of energy lost to friction.

Please don't just copy and paste, and thank you Dan cause you practically did it I just... elaborated more? I dunno. 

4 0
3 years ago
How many lines per mm are there in the diffraction grating if the second order principal maximum for a light of wavelength 536 n
grandymaker [24]

To solve this problem it is necessary to apply the concepts related to the principle of superposition and the equations of destructive and constructive interference.

Constructive interference can be defined as

dSin\theta = m\lambda

Where

m= Any integer which represent the number of repetition of spectrum

\lambda= Wavelength

d = Distance between the slits.

\theta= Angle between the difraccion paterns and the source of light

Re-arrange to find the distance between the slits we have,

d = \frac{m\lambda}{sin\theta }

d = \frac{2*536*10^{-9}}{sin(24)}

d = 2.63*10^{-6}m

Therefore the number of lines per millimeter would be given as

\frac{1}{d} = \frac{1}{2.63*10^{-6} }

\frac{1}{d} = 379418.5\frac{lines}{m}(\frac{10^{-3}m}{1 mm})

\frac{1}{d} = 379.4 lines/mm

Therefore the number of the lines from the grating to the center of the diffraction pattern are 380lines per mm

6 0
2 years ago
What is the volume of a bar of soap that is 9 cm long, 5 cm wide, and 2 cm high?
GalinKa [24]

Answer:

90cm

Explanation:

2x5=10

10x9=90

7 0
3 years ago
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