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Ahat [919]
3 years ago
15

The five values for a data set are: minimum = 0 lower quartile = 2 median = 3.5 upper quartile = 5 maximum = 10 Bruno created th

e box plot using the five values. What error did he make? The right whisker should go from 3.5 to 10. The left whisker should go from 0 to 2. The box should go from 2 to 3.5. The box should go from 3.5 to 5.
Mathematics
2 answers:
Alexxx [7]3 years ago
7 0

Answer: B

Step-by-step explanation:

horsena [70]3 years ago
5 0

Step-by-step explanation:

you need to check for outliers

2-1.5iqr

3.5=1.5iqr

1.5 iqr=5.25

so min has no ouliers but anything above 8.75 is an outlier, so you end the whisker there instead of 10 and use * to mark the other outliers

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<h3>3 Answers: Choice D, Choice E, Choice F</h3>

============================================================

Explanation:

The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.

Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.

Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.

We can verify this algebraically. For instance, if we weren't sure point E was  a solution or not, we would plug the coordinates into the inequality to get...

6x - 10y ≥ 9

6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)

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Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.

-----------

I'll show an example of something that doesn't work. Let's pick on point A.

We'll plug in (x,y) = (-1,1)

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