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Paladinen [302]

3 years ago

15

State if the polygons are similar. If they are, give the scale factor.

1 answer:

lutik1710 [3]3 years ago

5 0

Yes the scale factor is 2/3

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Factorise the following by taking out a common binomial factor.<br> 7(x - 3) - (x + 3)(x - 3)

g100num [7]

Step-by-step explanation:

7(x - 3) - (x + 3)(x - 3)

(x - 3)(7 - (x + 3))

(x - 3)(7 - x - 3)

(x - 3)(4 - x)

7 0

3 years ago

Read 2 more answers

What is the answer to this question please help

LuckyWell [14K]

Answer:

(x+5)(x-3)

Step-by-step explanation:

We can factor the equation to be

(x+5)(x-3)

5 0

3 years ago

What value of n makes the equation true?

dybincka [34]

1(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20 i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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4 0

1 year ago

estimate 0.00792398 to the nearest thousandth. Express your answer as a single-digit times a power of ten

Marianna [84]

Answer: $\approx8*10^{-3}$

Step-by-step explanation:

In order to round to the nearest thousandth, you must observe the digit to the right of the digit in the thousandth place and then:

If it is less than 5, you must round down.

If it is greater than or equal than 5, you must round up.

In this case, given the number:

$0.00792398$

You can notice that the digit to the right of the digit in the thousandth place is 9.

Since $9>5$ , you must round up. Then:

$0.00792398\approx0.008$

Finally, to express this as a single-digit times a power of ten, move the decimal point three places to the right. Then you get:

$\approx8*10^{-3}$

5 0

3 years ago

What is the approximate diagonal distance from one corner of a 3 inch by 5 inch index card to the opposite corner

77julia77 [94]

Answer:

5.83 inches

Step-by-step explanation:

The card is a rectangular shaped object, drawing a diagonal from one corner to the other, divides the rectangle into two right angled triangles with the diagonals as the hypothenuse.

Using Pythagoras theorem.

c^2 = a^2 + b^2

Given;

Side a = 3

Side b = 5

Substituting the given values;

c^2 = 3^2 + 5^2

c = √(9+25)

c = √34

c = 5.83 inches

7 0

3 years ago