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Fantom [35]
4 years ago
7

Consider an electron that is 10−10 m from an alpha particle (q = 3.2 × 10−19 C). (a) What is the electric field due to the alpha

particle at the location of the electron? (b) What is the electric field due to the electron at the location of the alpha particle? (c) What is the electric force on the alpha particle? On the electron?
Physics
1 answer:
FinnZ [79.3K]4 years ago
8 0

Answer:

a) 28.8×10^10N/C

b) 14.4×10^10N/C

c) Force on electron particle= 46.13×10^-9N

Force on the alpha= 146.08×10^-9N

Explanation:

Using the equation, E = kq/r^2

a) E = (8.99×10^9)×(3.2×10^-19) / (10^-10)^2

E = 28.8×10^-9N/C

b) E = kq/r^2

E = (8.99×10^9)×(1.602×10^-19)/(10^-10)^2

E= 14.4×10^10N/C

c) Felectron= E× q = (28.8×10^10)×(1.602×10^-19)

Felectron= 46.13×10^-9N

Force F on alpha = E× q= 14.4x10^10)×(3.2×10^-19)

F alpha= 146.08 ×10^-9N

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A bicycle travels 6.10 km due east in 0.210 h, then 11.30 km at 15.0° east of north in 0.560 h, and finally another 6.10 km due
Virty [35]

Answer:

Explanation:

Given

First bicycle travels 6.10 km due to east in 0.21 h

Suppose its position vector is r_1

r_1=6.10\hat{i}

After that it travels 11.30 km at 15^{\circ} east of north  in 0.560 h

suppose its position vector is r_2

r_{2}=11.30\left ( cos15\hat{j}+sin15\hat{i}\right )

after that he finally travel 6.10 km due to east in 0.21 h

suppose its position vector is r_3

r_{3}=6.10\hat{i}

so position of final position is given by

r=r_1+r_{2}+r_{3}

\vec{r}=15.12\hat{i}+10.91\hat{j}

\vec{v_{avg}}=\frac{\vec{r}}{t}

t=0.21+0.56+0.21=0.98 h

\vec{v_{avg}}=15.42\hat{i}+11.13\hat{j}

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For direction

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5 0
4 years ago
Heinrich hertz used properties of which type of wave to support the idea that light is also made of waves?.
Vsevolod [243]

Answer:

Hertz extended Maxwell's idea that light is produced by the interaction of electromagnetic fields. Waves produced a diffraction pattern. Results supported the wave theory of light.

7 0
2 years ago
Read 2 more answers
A total electric charge of 6.75 nC is distributed uniformly over the surface of a metal sphere with radius 20.0 cm. If the poten
djverab [1.8K]

Answer:

a) 60 V

b) 125 V

c) 125 V

Explanation:

<u>Given</u>

We are given the total electric charge q = 6.75 nC = 6.75x 10^-9 C distributed uniformly over the surface of a metal sphere with a radius of R = 20.0 cm = 0.020 m.  

<u>Required </u>

We are asked to calculate the potential at the distances

(a) r = 10.0 cm

(b) r = 20.0 cm

(c) r = 40.0 cm  

<u>Solution</u>

(a) Here, the distance r > R so, we can get the potential outside the sphere (r > R) where the potential is given by

V = q/4\pi∈_o                       (1)

r is the distance where the potential is measured and the term 1/4\pi∈_o equals  9.0 x 10^9 Nm^2/C^2. Now we can plug our values for q and r into equation (1) to get the potential V where r = 0.10 m  

V= 1*q/4\pi∈_o*r

 =60 V

(b) Here the distance r is the same for the radius R, so we can get the potential inside the sphere (r = R) where the potential is given by  

V = 1*q/4\pi∈_o*R                (2)    

Now we can plug our values for q and R into equation (2) to get the potential V where R = 0.20 m  

V = 1*q/4\pi∈_o*R

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(c) Inside the sphere the electric field is zero therefore, no work is done on a test charge that moves from any point to any other point inside the sphere. Thus the potential is the same at every point inside the sphere and is equal to the potential on the surface. and it will be the same as in part (b)  

V= 125 V

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3 years ago
Concept map for kinetic energy, work and power
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Kinetic energy: the energy of motion

Work: the change in kinetic energy

Power: the rate of work done

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. Mathematically, it is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

The work done an object is the amount of energy transferred; according to the energy-work theorem, it is equal to the change in kinetic energy of an object:

W=K_f - K_i

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K_i is the initial kinetic energy

Finally, the power is the rate of work done per unit time. Mathematically, ti can be expressed as

P=\frac{W}{t}

where

W is the work done

t is the time elapsed

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Answer:

0

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