(a)
The magnitude of the linear momentum of an object is given by
where
m is the object's mass
v is its speed
In this case, we have
(mass of the proton)
(speed of the proton)
So, the momentum is
b) 7.0 kg m/s
In this case, we have
m = 16.0 g = 0.016 kg (mass of the bullet)
v = 435 m/s (speed of the bullet)
By applying the same formula, the linear momentum is
c) 797.5 kg m/s
In this case, we have
m = 72.5 kg (mass of the sprinter)
v = 11.0 m/s (speed of the sprinter)
By applying the same formula, the linear momentum is
d)
In this case, we have
(mass of the Earth)
(speed of the Earth)
By applying the same formula, the linear momentum is
Answer:
no electric field line don't song closed loop.
Nothing, ATOMS lose or gain electrons to become IONS
<span>Two Na ATOMS lose 1 electron each and 1 S ATOM gains 2 electrons </span>
Answer:
1,170
Explanation:
Kinetic energy=1/2×m×velocity squared
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
We have then:
Horizontal = 9-9.2cos (58) = 4.124742769 N.
Vertical = 9.2sin (58) = 7.802042485 N
Then, the resulting net force is:
F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
Then by definition:
F = m * a
Clearing the acceleration:
a = F / m
a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
answer:
The magnitude of the body's acceleration is
2.941756275 m / s ^ 2