Terminal speed=136.7 m/s
the formula for the terminal speed is given by :
V= 
m= mass=75 kg
a= area=0.2 x 0.4=0.08 m²
ρ= density of air=1.23 kg/m³
C= drag constant =0.8
so V= 
v= 136.7 m/s
Answer:
a) Team A will win.
b) The losing team will accelerate towards the middle line with 0.01 m/
Explanation:
Given that Team-A pulls with a force , 
and Team-B pulls with a force , 
∵ 
The rope will move in the direction of force
.
∴ Team-A will win.
b) Considering both the teams as one system of total mass , 
Net force on the system ,
= 50-45 = 5N
Applying Newtons first law to the system ,
F = ma , where 'a' is the acceleration of the system.
Since , both the teams are connected by the same rope , their acceleration would be the same.
∴ 5 = 499×a
∴ a = 0.01 m/
Answer:
He also formulated his law of Universal Gravitation in the Principia, which states that every point mass attracts every single other point mass by a force pointing along the line intersecting both point.
Explanation: