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3 years ago

H(t)=-16t*2+16t=480 need help

1 answer:

3 0

I do not need any snarky remarks from you. I was trying to help. FOR EXAMPLE what am I solving for? Y intercept, X intercept. You don't get to get angry with me because I'm asking a simple question girl.

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Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Aleonysh [2.5K]

Given:

$f\mleft(x\mright)=e^{-x^3}$

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

$\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}$

Thus, y = 0 is the horizontal asymptote for the given function.

5 0

1 year ago

[] divided 1/3 =6/7.

Ganezh [65]

Answer:

6/21

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

3 years ago

There are 1073 students at Raine High School. 26 percent do not identify as male or female, 42 percent identify as female, and 3

irinina [24]

Don’t Identify- 278.98
Female- 450.66
Male- 343.36

Considering these are people, you probably will need to round either up or down. If you round it would be:

Don’t Identify- 279
Female- 451
Male- 343

3 0

3 years ago

Is 34.653 greater than 3.4653

NeX [460]

in 3.4653, there is one digit to the left of the decimal point, that is the ones position

in 34.653, there are 2 numbers to the left of the decimal point, the 3 is located in the tens place

so 34.653 is greater than 3.4653

4 0

3 years ago