Answer:
c= -20
x= 38
Explanation:
Solve for x and c by simplifying both sides of the equation, then isolating the variable.
hope this helps!
Let's to the first example:
f(x) = x^2 + 9x + 20
Ussing the formula of basckara
a = 1
b = 9
c = 20
Delta = b^2 - 4ac
Delta = 9^2 - 4.(1).(20)
Delta = 81 - 80
Delta = 1
x = [ -b +/- √(Delta) ]/2a
Replacing the data:
x = [ -9 +/- √1 ]/2
x' = (-9 -1)/2 <=> - 5
Or
x" = (-9+1)/2 <=> - 4
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Already the second example:
f(x) = x^2 -4x -60
Ussing the formula of basckara again
a = 1
b = -4
c = -60
Delta = b^2 -4ac
Delta = (-4)^2 -4.(1).(-60)
Delta = 16 + 240
Delta = 256
Then, following:
x = [ -b +/- √(Delta)]/2a
Replacing the information
x = [ -(-4) +/- √256 ]/2
x = [ 4 +/- 16]/2
x' = (4-16)/2 <=> -6
Or
x" = (4+16)/2 <=> 10
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Now we are going to the 3 example
x^2 + 24 = 14x
Isolating 14x , but changing the sinal positive to negative
x^2 - 14x + 24 = 0
Now we can to apply the formula of basckara
a = 1
b = -14
c = 24
Delta = b^2 -4ac
Delta = (-14)^2 -4.(1).(24)
Delta = 196 - 96
Delta = 100
Then we stayed with:
x = [ -b +/- √Delta ]/2a
x = [ -(-14) +/- √100 ]/2
We wiil have two possibilities
x' = ( 14 -10)/2 <=> 2
Or
x" = (14 +10)/2 <=> 12
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To the last example will be the same thing.
f(x) = x^2 - x -72
a = 1
b = -1
c = -72
Delta = b^2 -4ac
Delta = (-1)^2 -4(1).(-72)
Delta = 1 + 288
Delta = 289
Then we are going to stay:
x = [ -b +/- √Delta]/2a
x = [ -(-1) +/- √289]/2
x = ( 1 +/- 17)/2
We will have two roots
That's :
x = (1 - 17)/2 <=> -8
Or
x = (1+17)/2 <=> 9
Well, this would be your answers.
These ratios are not proportional.
Explanation:
If the ratio 8:32 were simplified, it would equal 1:4 because they can both be divided by 8. But since 16 x 4 does not equal 72, they cannot be divided by 4 to make a simplified ratio such as the first example.
Hope I helped, and good luck!
Answer:
960
Step-by-step explanation:
9600/10∧1=960
I would love to use substitution (It is simplier that way I guess)
solve your system of equations.
x+2y=−1;x−y=5
Solve x+2y=−1 for x:
x+2y+−2y=−1+−2y(Add -2y to both sides)
x=−2y−1
Substitute (−2y−1) for x in x−y=5:
x−y=5
−2y−1−y=5
−3y−1=5(Simplify both sides of the equation)
−3y−1+1=5+1(Add 1 to both sides)
−3y=6
−3y/−3 = 6/−3(Divide both sides by -3)
y=−2
Substitute (−2) for y in x=−2y−1:
x=−2y−1
x=(−2)(−2)−1
x=3(Simplify both sides of the equation)
So the answer is (x = 3 and y = -2)
