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Gnom [1K]
3 years ago
8

What are the roots of the quadratic function in the graph? -15 -5,3 -5,-3 -3,5

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0
The roots are -5 and 3
nasty-shy [4]3 years ago
4 0

Answer:

-5 and 3

Step-by-step explanation:

The roots of a quadratic function are also called the x intercepts.

The x intercepts are found by looking where where the quadratic equation crosses the x, or horizontal axis.

In this case, the quadratic equation crosses the x axis at (-5,0) and (3,0).

Therefore, our roots are -5 and 3

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Answer:

(13,9) I think

Step-by-step explanation:

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8 0
3 years ago
A roofer props a ladder against a wall so that the top of the ladder reaches a 30-foot roof that needs repair. If the angle of e
gizmo_the_mogwai [7]
Set this up like a right triangle with the height of the triangle as 30, the angle across from that side, the reference angle, as 55, and the base is your unknown, x.  This means that we have the angle, the side across from it, and the side adjacent to it.  That sounds like the tangent ratio to me!  Tangent of the angle is the side opposite over the side adjacent: tan(55)= \frac{30}{x}.  Solving for x: x= \frac{30}{tan(55)}.  Do that on your calculator in degree mode to get that the distance between the base of the ladder and the wall is 21 feet
5 0
4 years ago
Find the solution set to the inequality.<br><br> 4x - 1 &lt; 11
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4x - 1 < 11
Add 1 to both sides
4x < 12
Divide both sides by 4
x < 3
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4 0
3 years ago
Read 2 more answers
Given the function f(x) = –5|x + 1| + 3, for what values of x is f(x) = –12?
Alexus [3.1K]
The answer to your question is negative 52. hope i helped.
7 0
4 years ago
Read 2 more answers
Help with this please
aliina [53]
AB = 6 cm, AC = 12 cm, CD = ?

In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.

Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°

In order to find ∠BCA, use the law of sines:
 
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA

Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°

Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°

In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.

12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
3 0
3 years ago
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