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Gnom [1K]
3 years ago
8

What are the roots of the quadratic function in the graph? -15 -5,3 -5,-3 -3,5

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0
The roots are -5 and 3
nasty-shy [4]3 years ago
4 0

Answer:

-5 and 3

Step-by-step explanation:

The roots of a quadratic function are also called the x intercepts.

The x intercepts are found by looking where where the quadratic equation crosses the x, or horizontal axis.

In this case, the quadratic equation crosses the x axis at (-5,0) and (3,0).

Therefore, our roots are -5 and 3

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Which expression is equivalent to (3x−2)(x+6)
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What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
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\bf \begin{array}{llccll}&#10;term&value\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;a_1&-4096\\&#10;a_2&-4096r\\&#10;a_3&-4096rr\\&#10;a_4&-4096rrr\\&#10;&-4096r^3\\&#10;&64&#10;\end{array}\implies -4096r^3=64&#10;\\\\\\&#10;r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}&#10;\\\\\\&#10;r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\&#10;-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;r=-\frac{1}{4}\\&#10;a_1=-4096\\&#10;n=6&#10;\end{cases}&#10;\\\\\\&#10;a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
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