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castortr0y [4]
3 years ago
7

14(150+10d)+23(80+6d)​

Mathematics
2 answers:
algol133 years ago
4 0

Answer:

3940+278d

Step-by-step explanation:

1. Distribute 14 and 23 through their parenthesis,

2100 + 140d + 1840 +138d

2. Add the common terms,

3940+ 278d

dem82 [27]3 years ago
3 0
Do: 14x150+14x10d+23x80+23x6d
Hope this helps
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3 years ago
How do you solve 418.6 divided by 80.5 using long division
nataly862011 [7]
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3 0
3 years ago
Please help!!!! I need this to be done and I don't know how to do it.
Harman [31]
Q2) 58.08
Q3) I got 180 but not sure.
Q4) I got 138
Q5) I got 28.56 for this one.

Hope this helps.

3 0
3 years ago
Can someone please help ? <br> Factor.<br> 10x^5+5x^2−15
AnnyKZ [126]

Answer:

5(2x^5 + x^2 - 3)

Step-by-step explanation:

The only factor in common is 5, so you would have 5(2x^5 + x^2 - 3). That can't be factored further. IF the equation had been to the fourth degree on the first term rather than to the fifth degree, it could have been factored as 5(2x^2 -3)(x^2 +1).

4 0
3 years ago
What is 3 3/5 + 4 11/15=?
Vitek1552 [10]
Equal to 4.73 repeating, rounded is 4.7
3 0
3 years ago
Read 2 more answers
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