What equation demonstrate that the set of polynomials is not closed under the certain operations

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

It is not closed under division.

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Find the solution to the system of equations by substitution. x = y + 1 4x + 3y = -31

lorasvet [3.4K]

X = y + 1...so sub in y + 1 for x in the other equation

4x + 3y = -31
4(y + 1) + 3y = -31...distribute thru the parenthesis
4y + 4 + 3y = -31...subtract 4 from both sides
4y + 3y = -31 - 4....combine like terms
7y = - 35...divide both sides by 7
y = -35/7
y = - 5

now sub -5 in for y in either of the original equations to find x
x = y + 1
x = -5 + 1
x = -4

solution is (-4,-5)

8 0

3 years ago

Which equation is NOT true?

MrRissso [65]

I'm gonna say c I'm not shore though

7 0

2 years ago

A - g(x) = |x-5|+5 B - g(x) = |x-5| C - g(x) = |x|+5 D - g(x) = |x+5|+5

n200080 [17]

Answer:

$g(x) = |x| + 5$

Step-by-step explanation:

Since both the original and transformed graph have the same x value for their vertex, there was no horizontal shift. However the vertex shifted up. Specifically it shifted up 5 units. Therefore:

$g(x) = f(x) + 5$