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Hunter-Best [27]

3 years ago

6

Dan bought 35 pieces of candy. He gave 4 pieces to each of his friends. He only has 3 pieces left. Which equation, when solved f

or
X, gives the number of friends?

2 answers:

ehidna [41]3 years ago

8 0

Answer:

35 - 4x = 3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

35−4x=3

35+−4x=3

−4x+35=3

Step 2: Subtract 35 from both sides.

−4x+35−35=3−35

−4x=−32

Step 3: Divide both sides by -4.

-4x/−4 = −32/ −4

x=8

Svetlanka [38]3 years ago

5 0

Answer:

8 friends

Step-by-step explanation:

4 doesn't go evenly to 9 ppl so it would be 8 friends and 3 extra pieces

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What is 15 cm/year converted to inches per month? Round to the nearest tenth.

topjm [15]

Answer:

0.5 inches per month

Step-by-step explanation:

There are nearly 0.3937 inches in 1 cm, so

$1 \ cm \approx 0.03937 \ in\\ \\15\ cm\approx 5.9055\ in$

There are 12 months in the year, so'

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$15 \ cm/year\approx \dfrac{5.9055}{12}\ in/month\\\approx 0.492125\ in/month\\\approx 0.5\ in/month\\\\$

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4 years ago

April can mow 3/8 of an acre of grass in 45 minutes. How many acres of grass does April mow per hour?

Ulleksa [173]

April mows 4/8 of an acre of grass per hour
I got this answer because I divided 45÷3 and got 15. So, I know that 15×4=60 and in minutes that equals a hour. I changed 3/8 to 4/8 since it was multiplying 4×15 instead of 3×15.

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3 years ago

Find the zeros of the following

julia-pushkina [17]

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13 ) Go...

$f(x) = {x}^{2} - 2x$

$0 = {x}^{2} - 2x$

${x}^{2} - 2x = 0$

Factor x

$x(x - 2) = 0$

$x = 0 \: \: \: or \: \: \: x - 2 = 0$

$x = 0 \: \: \: \: or \: \: \: \: x = 2$

These are the zeroes.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

14 ) Go...

$f(x) = {x}^{3} + 9x + 11x - 21$

$0 = {x}^{3} + 9 {x}^{2} + 11x - 21$

${x}^{3} + 9 {x}^{2} + 11x - 21 = 0$

$(x - 1)(x + 3)(x + 7) = 0$

$x - 1 = 0 \: \: or \: \: x + 3 = 0 \: \: or \: \: x + 7 = 0 \\$

$x = 1 \: \: \: or \: \: \: x = - 3 \: \: \: or \: \: \: x = - 7 \\$

These are the zeroes.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

4 0

3 years ago

Sali throws an ordinary fair 6 sided dice once.

xenn [34]

a) 1/6

b) 1/36

c)

1H, 2H, 3H, 4H, 5H, 6H

1T, 2T, 3T, 4T, 5T, 6T

Step-by-step explanation:

a)

The probability of a certain event A to occur is given by

$p(A)=\frac{a}{n}$

where

a is the number of successfull outcomes, in which event A occurs

n is the total number of possible outcomes

In this problem, the event is

"getting a 6 when throwing a dice once"

We know that the possible outcomes of a dice are six: 1, 2, 3, 4, 5, 6, so we he have

$n=6$

The successfull outcome in this case is only if we get a 6, so only 1 outcome, therefore

$a=1$

So, the probability of this event is

$p(6)=\frac{1}{6}$

b)

In this case instead, we are throwing the dice twice.

The two throws of the dice are independent events (one does not depend on the other): the probability that two independent events A and B occur at the same time is given by the product of the individual probabilities,

$p(AB)=p(A)\cdot p(B)$

where

$p(A)$ is the probability that event A occurs

$p(B)$ is the probability that event B occurs

Here we have:

- Event A is "getting a 6 in the first throw of the dice". We already calculated this probability in part a), and it is

$p(A)=\frac{1}{6}$

- Event B is "getting a 6 in the second throw of the dice". Since the dice has not changed, the probability is still the same, so

$p(B)=\frac{1}{6}$

Therefore, the probability of getting a 6 on both throws is:

$p(66)=p(6)\cdot p(6)=\frac{1}{6}\cdot \frac{1}{6}=\frac{1}{36}$

c)

In this problem, we have:

- A dice that is thrown once

- A coin that is also thrown once

The dice has 6 possible outcomes, as we stated in part a):

1, 2, 3, 4, 5, 6

While the coin has two possible outcomes:

H = head

T = tail

So, in order to find all the outcomes of the two events combined, we have to combine all the outcomes of the dice with all the outcomes of the coin.

Doing so, using the following notation:

1H (getting 1 with the dice, and head with the coin)

The possible outcomes are:

1H, 2H, 3H, 4H, 5H, 6H

1T, 2T, 3T, 4T, 5T, 6T

So, we have a total of 12 possible outcomes.

4 0

3 years ago