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3 years ago

Which statements about the pattern are true?

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

8 0

All the correct answers are C and D.

snow_tiger [21]3 years ago

5 0

C.
Every term is a multiple of 3.
AND
D.
Every term is greater than the previous term.

are your answers

Hope this helps!

You might be interested in

The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. Find the variance and sta

Leviafan [203]

First get the average passing yards:

(3,832 + 3,779 + 3,655 + 3,642 + 3,579) / 5 = 3,697.4

Now get the squared residuals for each quarterback's passing yards. That is, compute the difference between each data and the average, then square the result. For example,

(3,832 - 3,697.4)^2 = 134.6^2 = 18,117.2

For the others, you should get squared residuals of

6,658.56

1,797.76

3,069.16

14,018.6

Take the sum of the squared residuals, then - since this is a sample, and not a population of all quarterbacks - divide the sum by 5 - 1 = 4 to get the variance:

(18,117.2 + 6,658.56 + 1,797.76 + 3,069.16 + 14,018.6)/4 = 10,915.3

The standard deviation is just the square root of the variance:

√(10,915.3) ≈ 104.48

5 0

3 years ago

Read 2 more answers

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

We have that AB || DC. By a similar argument used to prove that AEB ≅ CED,we can show that ≅ CEB by . So, ∠CAD ≅ ∠ by CPCTC. The

svp [43]

We have that AB || DC.

By a similar argument used to prove that AEB ≅ CED,we can show that (AED) ≅ CEB by (SAS) . So, ∠CAD ≅ ∠ (ACB) by CPCTC. Therefore, AD || BC by the converse of the (
ALTERNATE INTERIOR ANGLES) theorem. Since both pair of opposite sides are parallel, quadrilateral ABCD is a parallelogram

1. AED
2. SAS
3. ACB
4. ALTERNATE INTERIOR ANGLES

7 0

2 years ago

Read 2 more answers

Simplify each of the following ratios.<br>e) 2/3 : 3/2 : 5/8

Snezhnost [94]

Answer:

32/45

Step-by-step explanation:

2/3 : 3/2 : 5/8

Remember, a ratio and a fraction are both division. Therefore you can rewrite the problem like so:

2/3 ÷ 3/2 ÷ 5/8

Dividing fractions is the same as multiplying them by the reciprocal.