Question

Lesson 10: Congruent Triangles ._.

Answer 1

#1 is A
#2 IS c
#3 is B

Answer 2

Answer:

Step-by-step explanation:

The congruence $MN \cong PR$ is false, because they are not corresponding sides.

The corresponding sides are:

$MN \cong PQ\\NO \cong QR\\MO \cong PR$

On the other hand, if $\triangle ABC \cong \triangle PQR$, then $\angle Q \cong \angle B$.

We know that $m\angle Q=8v-6$ and $m \angle B=3v+4$, but they are equal, so

$8v-6=3v+4\\8v-3v=6+4\\5v=10\\v=2$

Then,

$m\angle Q=8v-6=8(2)-6=16-6=10\\m \angle B=3v+4=3(2)+4=6+4=10$

Therefore, those angles are equal to 10°.

In the second image, the given triangles have the following congruence:

$\angle DAB \cong \angle CAB\\\angle DBA \cong \angle CBA$

Also, they have side AB in common.

Therefore, $\triangle ABC \cong \triangle ABD$, by ASA.