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Elden [556K]
3 years ago
5

Lesson 10: Congruent Triangles ._.

Mathematics
2 answers:
spayn [35]3 years ago
3 0
#1 is A
#2 IS c
#3 is B
liberstina [14]3 years ago
3 0

Answer:

Step-by-step explanation:

The congruence MN \cong PR is false, because they are not corresponding sides.

The corresponding sides are:

MN \cong PQ\\NO \cong QR\\MO \cong PR

On the other hand, if \triangle ABC \cong \triangle PQR, then \angle Q \cong \angle B.

We know that m\angle Q=8v-6 and m \angle B=3v+4, but they are equal, so

8v-6=3v+4\\8v-3v=6+4\\5v=10\\v=2

Then,

m\angle Q=8v-6=8(2)-6=16-6=10\\m \angle B=3v+4=3(2)+4=6+4=10

Therefore, those angles are equal to 10°.

In the second image, the given triangles have the following congruence:

\angle DAB \cong \angle CAB\\\angle DBA \cong \angle CBA

Also, they have side AB in common.

Therefore, \triangle ABC \cong \triangle ABD, by ASA.

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Solve using the pathagorean theorem​
seropon [69]

Answer:

2 sqrt(13)

Step-by-step explanation:

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2 years ago
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DiKsa [7]

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a. f<g is one of them. On the number line, g is closest to 0, meaning it is greater than f.

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Step-by-step explanation:

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3 years ago
Put these numbers in order from least to greatest 1/8, -0.333, -1/7
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Answer:

-0.333, -1/7, 1/8

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