Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula
As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula
Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
AB is bisected by CD (TRUE). This is True because E is the midpoint between A and B and CD passes through E
CD is bisected by AB (FALSE) CD is bisected by point F and not AB
AE = 1/2 * AB (TRUE) since E is the midpoint of AB , E divides AB into two equal halves
EF = 1/2 * ED (FALSE) The true statement would have been CF = 1/2* CD
FD = EB (FALSE) sinc we do not know if CD and AB are of the same lengths
CE + EF = ED (TRUE) since F is the midpoint the sum of CE and EF is equal to ED
15mph. 45/3=15 . She biked 15 miles per hour .
The answer is white. Hope this helps
