There are 6, you'd think there would be 8 but the answer is actually 6. A diagonal is a line segment that connects to vertices, the two vertices chosen do not count when forming the triangle, two vertices that are adjacent to that chosen vertex are NOT included when forming the diagonal. It's confusing, but I hope this helps. If you have any follow up questions I'd love to answer them.
Answer:
7/18
Step-by-step explanation:
²
=((2*7)+4)/7
2*7=14
14+4=18
18/7⇒7/18
Answer:
what is that?
Step-by-step explanation:
Answer:
Q 12 roots of the equation
![2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-6%2B1%3D0%20%5C%5C%3D%20%28x-%5Cfrac%7B%5Csqrt%7B10%7D%20%7D%7B2%7D%29%28x%2B%5Cfrac%7B%5Csqrt%7B10%7D%20%7D%7B2%7D%29%5C%5C)
∝ = ![\frac{\sqrt{10} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B10%7D%20%7D%7B2%7D)
β = ![-\frac{\sqrt{10} }{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%7B10%7D%20%7D%7B2%7D)
no matter if u oppose the root
(i) 2(
)
+2
(
)+2(
(ii)(
- 3 (
)(
) + (
) = ![\frac{25}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7B2%7D)
Q 13 roots of equation
![4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443](https://tex.z-dn.net/?f=4x%5E%7B2%7D%20-3x-4%3D0%5C%5C%5Calpha%20%3D%20-0.693%5C%5C%5Cbeta%20%3D%201.443)
the roots of the second equation are
x1 = 1/3(-0.693) = -0.231
x2 = 1/3(1.443) = 0.481
the equation is
(x+0.231)(x-0.481)=0
![x^{2}-\frac{1}{4} x-\frac{1}{9}](https://tex.z-dn.net/?f=x%5E%7B2%7D-%5Cfrac%7B1%7D%7B4%7D%20x-%5Cfrac%7B1%7D%7B9%7D)
Given:
The figure of triangle ABC.
The area of the triangle ABC is D.
![m\angle B=\sin ^{-1}(\dfrac{m}{n})](https://tex.z-dn.net/?f=m%5Cangle%20B%3D%5Csin%20%5E%7B-1%7D%28%5Cdfrac%7Bm%7D%7Bn%7D%29)
To find:
The value of m and n in the given expression.
Solution:
Let h be the height of the triangle ABC.
Area of a triangle is:
![Area=\dfrac{1}{2}\times base\times h](https://tex.z-dn.net/?f=Area%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20h)
Where, b is the base and h is the height of the triangle.
![Area=\dfrac{1}{2}\times a\times h](https://tex.z-dn.net/?f=Area%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%20h)
The area of the triangle ABC is D.
![D=\dfrac{1}{2}\times a\times h](https://tex.z-dn.net/?f=D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%20h)
![2D=ah](https://tex.z-dn.net/?f=2D%3Dah)
...(i)
In a right angle triangle,
![\sin \theta =\dfrac{Perpendicular}{Hypotenuse}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%3D%5Cdfrac%7BPerpendicular%7D%7BHypotenuse%7D)
![\sin B =\dfrac{h}{c}](https://tex.z-dn.net/?f=%5Csin%20B%20%3D%5Cdfrac%7Bh%7D%7Bc%7D)
[Using (i)]
...(ii)
We have,
...(iii)
On comparing (ii) and (iii), we get
![m=2D](https://tex.z-dn.net/?f=m%3D2D)
![n=ac](https://tex.z-dn.net/?f=n%3Dac)
Therefore, the required values are
.