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podryga [215]
3 years ago
6

Multiply

Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0

Answer:

option a

hope it helps u

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What is 64 minutes (1 hour and 4 minutes) as mixed number? I'm pretty sure its something like this:
Trava [24]

Answer: 1  4/60

Step-by-step explanation

64 is greater then 60 . 60 = 1 hour so  64 minutes = 1 whole 4 over 60

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Brainliest for best joke
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Answer:

What happens if you put a booger on a tissue. The tissue starts to boogey dance.

Step-by-step explanation:

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Write an equation for your trend line?
Soloha48 [4]
Find two points on the graph that the line crosses through almost perfectly. It looks like (1,10) and (9,1) will do.

Use them to compute the slope:
m = (1 - 10) / (9 - 1)
= -9/8

Then set up the "point-slope form":
y - y0 = m * (x - x0)

You choose some point (x0, y0) that the line crosses through. We already know the line passes through (1,10) pretty well, so let's use that.

x0 = 1
y0 = 10

Now finish plugging into the equation:
y - 10 = -9/8 * (x - 1)

The above equation will work fine for an answer, but let's go a step further and solve for y.

y - 10 = -9/8x + 9/8
y = -9/8x + 9/8 + 10
y = -9/8x + 9/8 + 80/8
y = -9/8x + (9 + 80)/8
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4 0
4 years ago
How is the graph of the parent function y=x² transformed to produce the graph of y=3(x+1)²?
Anna11 [10]

Answer:

Step-by-step explanation:

Remark

Always the easiest way to study these questions is to get a graph. The one below shows

Red: y = x^2

Blue: y= 3(x + 1)^2

You will notice that (x+1)^2 shifts the graph Left -- the opposite to what you might think.

The 3 is a little harder. It narrows the red mother graph. Which choice says that?

The choice is between b and d. Why. Because the blue graph is to the left of the red one.

You have to learn the meaning of compressed. A better word might be narrows.

Answer

B

7 0
2 years ago
Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop
Archy [21]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}

4 0
1 year ago
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