3 years ago

CAN ANYONE HELP ME ANSWER THIS

Mathematics

2 answers:

topjm [15]3 years ago

7 0

Answer:

its dependent

Step-by-step explanation:

the two events cannot happen on their own, so they depend on each other

Step2247 [10]3 years ago

6 0

I think is dependent

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I need help ASAP please

trapecia [35]

Answer:

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = $\frac{1}{\sqrt{2} }$ , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{3}{c}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

c = 3 $\sqrt{2}$

5 0

3 years ago

A survey of a random sample of voters shows that 29% plan to vote for Martin and 71% plan to vote for

Iteru [2.4K]

Range=±7%

Martin=71%, Lang=29%

Range for Martin=71%±7%

So, highest %=71%+7%=78%

Lowest %=71%-7%=64%

Therefore,range for Martin is between 64%-78% which is 14%

3 0

3 years ago

The range of the function RK) = R +26+1 İS {25, 643. What is the function's domain?

frozen [14]

Answer:

Step-by-step explanation:

hope this helped! please let me know if im wrong

4 0

3 years ago

Read 2 more answers

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

Anvisha [2.4K]

Answer:

Probability will be 0.5779

Step-by-step explanation:

Number of tablets n = 19

Probability of defect rems that is p = 0.03

Here number of trials is fixed and probability of success = 0.03

Here p = 0.03

So q = 1 - p = 1 -0.03 = 0.97

By using binomial distribution

Probability is given by $^nC_rp^rq^{n-r}$

So P(0 or 1) = $^{19}C_0{0.03}^0{0.97}^{19-0}+^{19}C_1{0.03}^1{0.97}^{19-1}=0.5606+0.0173=0.5779$

4 0

3 years ago

Solve for the value of x: x/2 + x/3 = 2x/5 + 3 , also I need a very thorough explanation for this.

Alona [7]

Answer:

$x=\frac{90}{13} .$

Step-by-step explanation:

$\frac{x}{2} +\frac{x}{3} =\frac{2x}{5} +3;$

$30*(\frac{x}{2} +\frac{x}{3} )=30*(\frac{2x}{5} +3);$

15x+10x=12x+90; ⇔ 13x=90;

$x=\frac{90}{13}.$

8 0

2 years ago

CAN ANYONE HELP ME ANSWER THIS ​

CAN ANYONE HELP ME ANSWER THIS