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Rina8888 [55]
4 years ago
6

Consider line A whose equation is y = -10x + 8. If line B is perpendicular to line A and has a y-intercept at y = 3, what is the

equation for line B?
A.
y = -10x + 3
B.
y = 10x + 3
C.
y = 1

10 x + 3
D.
y = - 1

10 x + 3
Mathematics
1 answer:
r-ruslan [8.4K]4 years ago
7 0

Answer:

C) . y=(1/10)x+3

Step-by-step explanation:

Given the equation of the line is y=-10x+8

It is in the form of y=mx+c where m is the slope of the line. Now on comparision we get m1=-10.

We knoew that two lines are perpendicular iff the product of their slopes is equal to -1.

m1*m2=-1

the slope of the recquired line =\frac{-1}{-10}=\frac{1}{10}

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept

Given the y intercept of the recquired line (b)=3

The recquired line is

y=mx+b

y=(1/10)x+3

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3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

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Step-by-step explanation:

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Nady [450]
We know that
<span>When two chords intersect each other inside a circle, the products of their segments are equal (</span>Intersecting Chord Theorem)<span>
</span>so
in this problem
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Answer:

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m = 20

c = 20 (20) = 400

6 0
3 years ago
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