Question

Consider line A whose equation is y = -10x + 8. If line B is perpendicular to line A and has a y-intercept at y = 3, what is the equation for line B?
A.
y = -10x + 3
B.
y = 10x + 3
C.
y = 1

10 x + 3
D.
y = - 1

10 x + 3

Answer 1

Answer:

C) . y=(1/10)x+3

Step-by-step explanation:

Given the equation of the line is y=-10x+8

It is in the form of y=mx+c where m is the slope of the line. Now on comparision we get m1=-10.

We knoew that two lines are perpendicular iff the product of their slopes is equal to -1.

$m1*m2=-1$

the slope of the recquired line =$\frac{-1}{-10}$=$\frac{1}{10}$

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept

Given the y intercept of the recquired line (b)=3

The recquired line is

y=mx+b

y=(1/10)x+3