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Luden [163]
3 years ago
14

a powerful motorcycle can accelerate from rest in 27 m/s in only 4.9 s. How far does it travel in that time?

Physics
1 answer:
Art [367]3 years ago
4 0

kinematic equation

dist=1/2x27/4.9 x 4.9  4.9

dist = 1/2x27x4.9

about 75m

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Help pls! <br> Explain if you think we should continue to use geothermal power in the future
zhuklara [117]

Answer:

Geothermal power can provide consistent electricity throughout the day and year - continuous baseload power and flexible power to support the needs of variable renewable energy resources, such as wind and solar. Sustainable Investment.

Explanation:

THIS IS WHY WE SHOULD USE GEOTHERMAL ENERGY IN FUTURE

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4 0
3 years ago
Longitudinal waves travel through a series of ____ and ____
Anastaziya [24]

Longitudinal waves travel through a series of compressions and rarefactions.

7 0
4 years ago
Light and sound waves both share what characteristic?
egoroff_w [7]

Answer:

light and sound are both trasverse waves

Explanation:

7 0
3 years ago
In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s . As he moves through hi
Inessa [10]

Given Information:

Initial speed = u = 3.21 yards/s

Acceleration = α  = 1.71 yards/s²

Final speed = v = 7.54 yards/s

Required Information:

Distance = s = ?

Answer:

Distance = s = 13.61

Explanation:

We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

We know from the equations of motion,

v² = u² + 2αs

Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

Re-arranging the above equation for distance yields,

2αs = v² - u²

s = (v² - u²)/2α

s = (7.54² - 3.21²)/2×1.71

s = 46.55/3.42

s = 13.61 yards

Therefore, the runner traveled a distance of 13.61 yards before being tackled.

8 0
3 years ago
A sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?
Alja [10]

Answer:

887.1Hz

Explanation:

Given parameters:

Speed of sound wave  = 330m/s

Wavelength  = 0.372m

Unknown:

Frequency  = ?

Solution:

To solve this problem, we use the expression below:

             Speed  = Frequency x wavelength

            330  = Frequency x 0.372

   Frequency  = 887.1Hz

5 0
3 years ago
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