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il63 [147K]
3 years ago
14

A model airplane with mass 0.5 kg hangs from a rubber band with spring constant 45 N/m. How much is the rubber band stretched wh

en the model airplane hangs motionless?
Physics
2 answers:
e-lub [12.9K]3 years ago
8 0
Multiply 0.5 by 9.8 then divide it by 45. 0.11m
Contact [7]3 years ago
3 0

Answer:

0.109 m (10.9 cm)

Explanation:

The weight of the airplane hanging from the rubber band is given by the product between its mass (0.5 kg) and the acceleration due to gravity (g=9.8 m/s^2):

W=mg=(0.5 kg)(9.8 m/s^2)=4.9 N

This is the force that stretches the rubber band, according to Hook's law:

F=kx

where

k = 45 N/m is the spring constant

x is the stretching of the spring with respect to its equilibrium position

Substituting F = 4.9 N and re-arranging the formula, we get:

x=\frac{F}{x}=\frac{4.9 N}{45 N/m}=0.109 m=10.9 cm

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Two elevators begin descending from the same height. Elevator A has descended 4 feet after one second, 9 feet after two seconds,
solniwko [45]

Answer:

a) y = 400 ft  b) y = 350 ft

Explanation:

We can solve that problem with kinematic relationships

    y = v₀ t + ½ a t²

Let's apply this equation to the elevator 1

     y₁ = v₀ t₁ + ½ to t₁²

time t= 1 s

    y₁ = v₀ 1 + ½ a 1²

    y₁ = v₀ + ½ a

For t = 2s

    y₂ = v₀ 2 + ½ a 2²

    y₂ = 2 v₀ + 2 a

Let's write the equations and solve the system

    4 = v₀ + ½ a

    9 = 2 v₀ + 2 a

Let's multiply the first by -2

    -8 = -2v₀ -a

     9 = 2v₀ + 2 a

Let's add

      1 = a

We replace in the first

      4 = v₀ + ½ 1

      v₀ = 4- 1/2

      v₀ = 3.5

The equation for the first elevator is

      y = 3.5 t + ½  t²

For t = 10 s

      y = 3.5 10 + ½ 10²  

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t = 1s

     y₁ = v₀ 1 + ½ a 1²

     3.5 = v₀ + ½ a

t = 2 s

     y₂ = v₀ 2 + ½ a 2²

     6.5 = 2 v₀ +2 a

multiply by -2

    -7 = -2 v₀ - a

     6.5 = 2 v₀ + 2 a

Let's add

    -0.5 = a

I replace in the first equation

    3.5 = v₀ + ½ (-0.5)

    v₀ = 3.5 + 0.25

    v₀ = 3.75

The equation is

    y = 3.75 t -0.25 t²

For t = 10s

    y = 3.75 10 - 0.25 10²

   y = 350 ft

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yulyashka [42]

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