Given that force is applied at an angle of 30 degree below the horizontal
So let say force applied if F
now its two components are given as


Now the normal force on the block is given as



now the friction force on the cart is given as



now if cart moves with constant speed then net force on cart must be zero
so now we have




so the force must be 199.2 N
Answer:
114.32195122 but Round your answer to three significant figures.) is 114
Explanation:
Just took the test
Answer:
N = 19.6 N
Explanation:
Given that,
Mass of a block, m = 2000 g
1 kg = 1000 g
It means, 2000 g = 2kg
We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :
N = mg, g is acceleration due to gravity
N = 2 kg × 9.8 m/s²
N = 19.6 N
So, the normal force acting on the block is 19.6 N.
Answer:
Explanation:
Animal cells and plant cells share the common components of a nucleus, cytoplasm, mitochondria and a cell membrane. Plant cells have three extra components, a vacuole, chloroplast and a cell wall.
Nothing can be determined from the curve without seeing the curve.