Work = Force* Distance
2000*1000=2000000
Power = Work/Time
2000000/45=<span>44444.44 Watts</span>
The answer is true I did that test befor
As we know that efficiency of engine is given as

also we know that

given that

efficiency = 21%
now we have




now we have

Answer:
Speed of second car will be 57.17 m/sec
Explanation:
We have given lead car travels = 44 laps
1 laps = 1.34 km = 1340 m
So total distance = 1340×44 = 58960 m
Speed of lead car = 55.9 m/sec
We know that 
As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m
So speed of second car will be 