The point slope form of a line is written as y - y1 = m(x -x1)
Where m is the slope and x1 and y1 are the points on the line.
You are told the slope is 3 and the point is (2,-1/2)
x1 is 2 and y1 is -1/2
Replace those in the equation to get:
y- (-1/2) = 3(x-2)
Simplify to get the final answer:
y + 1/2 = 3(x-2)
16 cm.
This is because one side of the hexagon is half of one side of the square. Therefore, you multiply 8 by 2. 8x2 = 16
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
A = P(1 + rt)
Where:
<span>·
</span>A = Total Accrued Amount (principal + interest)
<span>·
</span>P = Principal Amount
<span>·
</span>I = Interest Amount
<span>·
</span>r = Rate of Interest per year in decimal; r = R/100
<span>·
</span>R = Rate of Interest per year as a percent; R = r * 100
<span>·
</span>t = Time Period involved in months or years
A = 15,000(1+ 0.07(5))
A = 20,250 they acquired in total for 5 years
The yearly amount the get is 15,000 xx 0.07 = $ 1050 per
year
So in the next 25 years addition of 1050x25 = $26250 they
will get
