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nirvana33 [79]
4 years ago
7

Kim Sperazo is a sign-language interpreter. She earns

Mathematics
2 answers:
defon4 years ago
7 0

Answer:

$992.33

Step-by-step explanation:

The regular earnings of Kim Sperazo = $19.65 per hour

Her earning for overtime = $19.65 × 1.5

                                          = $29.475

She worked her regular 40 hours plus 7 hours of overtime.

Her total pay for the week = (19.65 × 40) + (29.475 × 7)

                                            = $786 + $206.325

                                           = $992.325 ≈ $992.33

Her total pay was $992.33 for the week.

olganol [36]4 years ago
6 0

Answer:992.325

Step-by-step explanation:

40×19.65+(7(19.65×1.5)

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Xelga [282]

Answer:

1) The graph is as shown at the attached figure.

2) The line passes with (1,-3) and (2,-2)

Step-by-step explanation:

graph the line that passes with (3,-1) and has a y-intercept of -4

y-intercept is the value of y when x = 0

So, the line passes with (0 , -4)

The general form of the line  y = mx + c

Where m is the slope and c is y-intercept

given y-intercept = -4 ⇒ ∴ c = -4

using the other point to find m

So, when x = 3 , y = -1

So,  -1 = 3m - 4

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7 0
3 years ago
All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage
tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}

Now, we can calculate the standard deviation as:

\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}

Answer: the standard deviation of this population is approximately 10.33

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