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dezoksy [38]
3 years ago
15

Help I will mark your as brainliest or what ever and 10 points

Mathematics
1 answer:
const2013 [10]3 years ago
7 0
Question 20

Total Surface Area = (4 x 8) + (5 x 8) + (8 x 3) +  2(1/2 x 4 x 3)
Total Surface Area = 108 cm²

Question 21

Total Surface Area = 2 (π x 4²) + (π x (4x2) x 20 ) 
Total Surface Area = 603 cm² (Nearest whole number)

Question 22

Total Surface Area = (20 x 5) + (12 x 20) + (20 x 13) + 2 ( 1/2 x 12 x 5)
Total Surface Area = 660 In²

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bekas [8.4K]
Why is everything due tomorrow xD. Also im sorry but I dont understand this either.
5 0
3 years ago
How do you solve the following equation: 5-(2x-3)=-8+2x
kirza4 [7]
I believe it would be done like this:
subtract 2x-8 from both sides. then use cubric formula.
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4 0
3 years ago
2.375 in expanded form
kari74 [83]

Answer:

2375^-3

Step-by-step explanation:

Move the decimal place from 2.375 to the back of the number so it should look like this, 2375.

Than move the decimal place back to its original spot and count the amount of spaces you move. Remember, if you move forward, your exponent should be negative. For example, if the problem is 6.321, you would move the decimal place to the back like this, 6321. And then move it back to where it originally was, 6.321, the amount of spaces I moved was 3 spaces and I moved forward so It would be 6.321^-3

6 0
2 years ago
A college has a 30% completion rate, meaning that 30% of all students who start at the college complete the goal they set. The p
RSB [31]

Answer:

45%

Step-by-step explanation:

For simplicity, let use assume there are 100 students in the school.

No. of students to complete college = (30/100) x 100 = 30 Students

President wants to increase by 50% = (50/100) x 30 = 15 Students

New set goal = 30 + 15 = 45 students.

Total number of students = 100 students

Therefore;

Rate goal % = (45/100) x 100% = 45%

4 0
2 years ago
Which graph shows a negative rate of change for the interval 0 to 2 on the x-axis
Lena [83]

Answer:

-2

Step-by-step explanation:

3 0
3 years ago
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