All categories

3 years ago

What do large circus animals wear to keep their legs warm worksheet 2.10 answers

2 answers:

3 0

I bet this question is a science joke. My answer for this would be Elepants. Large circus animals wear elepants to keep their legs warm. People wear pants to keep the bottom parts warm and one of the large animals that we can see in a curcus are elephants. So, yeah, elepants it is.

DanielleElmas [232]3 years ago

3 0

<h2>Answer:</h2>

<u>They don't need anything to wear, they can change grow furs during winter naturally.</u>

<h2>Step-by-step explanation:</h2>

The body temperature of some animals drops and heart rate slows down to conserve energy. On the other side there are certain animals that adapt to the change in climate. They grow warmer fur or feathers or grow a layer of insulating fat. For mammals without hair, a thick layer of fat tissue is present which helps to insulate an animal's body and keep them warm.

You might be interested in

What expression is equivalent to x2 - 49?

aleksley [76]

Answer:

Expla:

x²-49

x²-7²

= (x+7)(x-7)

7 0

3 years ago

Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was $ 4 3 . 2 5 $43.25dollar sign

Mrrafil [7]

Can you try typing the problem instead of using voice to text. sorry I could not understand

3 0

3 years ago

Solve for y.<br> 8+4y= -8

Andrew [12]

Answer:

-4

Step-by-step explanation:

8+4y= -8

4y= -8 -8

4y= -16

divide both sides by the coeffient of the variable. in this case divide both sides by 4

y=-4

7 0

3 years ago

Read 2 more answers

10. A wire is of length 264 cm. It is bent into a circle. What is the radius of the circle so obtained. If it

Luden [163]

Answer:

$r = 42$ --- radius

$L = 66$ -- Length of the square

Step-by-step explanation:

Given

$Length = 264cm$

Solving (a): Find the radius (when it formed a circle).

The length of the wire represents the circumference (C) of the wire.

So, we have:

$C = 2\pi r$

Make r the subject

$r = \frac{C}{2\pi}$

Substitute 264 for C

$r = \frac{264}{2\pi}$

$r = \frac{132}{\pi}$

Take $\pi$ as 22/7

$r = \frac{132}{22/7}$

$r = \frac{132*7}{22}$

$r = \frac{924}{22}$

$r = 42$

Solving (b): Find the side length (when it formed a square).

The length of the wire represents the perimeter (P) of the wire.

So, we have:

$P = 4L$

Make L the subject

$L = \frac{1}{4}P$

Substitute 264 for P

$L = \frac{1}{4}*264$

$L = 66$

4 0

3 years ago

Hey can you please help me posted picture of question

MArishka [77]

It would be letter D - 3648.

The probability of winning is 0.76 and the probability of losing is 0.24.

In each simulation the probability of winning exactly one match is: P(win one match) = 2C1 x 0.76 x 0.24 = 0.3648

Multiply the result by 10,000 simulations to get the expected number of times that exactly one match is won.
10,000 x 0.3648 = 3648 times.

4 0

4 years ago