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NISA [10]
3 years ago
11

Im having a really bad day help me pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
2 answers:
Mama L [17]3 years ago
5 0

Hi there!

\large\boxed{0.5 \text{ hours, or } 30 \text{ minutes}}

Use the formula d / s = t to solve for the time needed for each:

Distance = 20 miles

(J)

20 m / 10 mph  = 2 hours

(B)

20 m / 8 mph = 2.5 hours

Subtract the times to find the amount of time necessary to wait:

2.5 - 2 = 0.5 hours or 30 minutes.

lara31 [8.8K]3 years ago
3 0
He waited 30 minutes hope your day gets better!
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yall i kinda need a bit of help The perimeter of the shape is 54 centimeters. What is the value of y? im super confused
gogolik [260]
Y= 9 because 54 divided by 6 sides = 9
4 0
3 years ago
Read 2 more answers
Subtract <br><br> \frac{3n+2}{n-4}-\frac{n-6}{n+4}
aalyn [17]
(3n+2)/(n-4) - (n-6)/(n+4)

common denominator (n-4)(n+4)

{(n+4)(3n+2)-(n-4)(n-6)}/{(n-4)(n+4)}

Use the foil method:

{(3n²+14n+8)-(n²-10n+24)}/{(n-4)(n+4)}

distribute negative sign:

{(3n²+14n+8-n²+10n-24)}/{(n-4)(n+4)}

subtract:

(2n²+24n-16)/{(n-4)(n+4)}

take out 2:

2{n²+12n-8}/{(n-4)(n+4)}

 
4 0
3 years ago
Read 2 more answers
Equation 1: m = 8 + 2n
slava [35]

Answer:

1:×4

m×4=(8+2n)×4

4m=32+8n

now,

1:×4 - 2:

4m-4m = 32+8n -4+4n

0=(32-4) +(8n-4n)

0=28+4n

28=-4n

n= -7

n=-7. 1:,

m=8+2n

m=8+2×(-7)

m=8-14

m=-6

7 0
2 years ago
Please help ASAP
gtnhenbr [62]

Put the value of x = -2 to the equation of the function y = -4x + 3:

y = -4(-2) + 3 = 8 + 3 = 11

<h3>Answer: A. (-2, 11)</h3>
3 0
3 years ago
Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

x:\text{Time} \\ \\ y:\text{Number of teams registered}

We also know that each week 6 teams register to participate, so:

\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

y=6x

In conclusion, <em>the linear model (first graph below) is the one that bests represents  the relationship between time and the number of teams registered.</em>

7 0
3 years ago
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