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3 years ago

9

Based on the dartboard shown below, what is the probability of a random throw hitting a section that is worth 1 point or is yell

ow?

1 answer:

Goryan [66]3 years ago

3 0

Answer:

B 3/4

Step-by-step explanation:

6/8 triangles meet the yellow or worth 1 specification, so reduce that and 3/4

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The equation ( ) has no solution.

trasher [3.6K]

Answer:

i dont see the equation

Step-by-step explanation:

sorry

6 0

3 years ago

Read 2 more answers

Factor out the GCF -2x^2 - 4x - 6

andrew-mc [135]

The Greatest Common factor(GCF) of -2x^2-4x-6 is -2(x+1)(x-3)

<h3>What is Greatest Common Factor?</h3>

The greatest common factor (GCF) is the largest factor two or more numbers have in common

From the question,

-2x^2-4x-6

By collecting like terms

-2(x^2-2x-3)

By factoring x^2-2x-3

-2(x^2-3x+1x-3)

Collecting like terms

-2(x^2-3x)+(x-3)

-2(x(x-3)+1(x-3))

-2(x+1)(x-3)

hence -2(x+1)(x-3) is the Greatest Common factor of -2x^2-4x-6 is

Learn more about Greatest Common factor on:brainly.com/question/219464

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3 0

1 year ago

In parallelogram RSTU, what is SU?

serious [3.7K]

Because S and U are the opposite vertices of the <span>parallelogram RSTU,
so SU is a diagonal of this </span>parallelogram.

5 0

4 years ago

The isosceles triangle has a perimeter of 7.5m. Which equation can be used to find the value of x if the shortest side, y, measu

Alexus [3.1K]

2.1 +2x=7.5
2x=7.5-2.1
2x=5.4
x=2.7

3 0

3 years ago

Read 2 more answers

Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

or

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

7 0

1 year ago