Question

If you roll a six-sided die, what is the probability you will obtain greater than a 2?

Answer 1

$|\Omega|=6\\ |A|=4\\\\ P(A)=\dfrac{4}{6}=\dfrac{2}{3}\approx67\%$

Answer 2

If we will roll a fair die then the outcomes wil be 1,2,3,4,5,6.

Hence, the total number of events= 6

3,4,5 and 6 are greater than 2.

So, there's 4 events which are greater than 2.

Now the formula to find the probability is:

probability=$\frac{Number of events more than 2}{Total number of events.}$

=$\frac{4}{6}$

=$\frac{2}{3}$

So, the probability of getting greater than a 2 is 2/3.