Answer:
<h3>The diameter is 4cm</h3>
Step-by-step explanation:
Volume of a sphere is
Where r is the radius
diameter = radius × 2
To find the diameter we must first find the radius
Volume = 34cm³
That's
![34 = \frac{4}{3} \pi {r}^{3} \\ \\ 34 \times 3 = 4\pi {r}^{3} \\ \\ 102 = 4\pi {r}^{3} \\ {r}^{3} = \frac{102}{4} \pi \\ \\ r = \sqrt[3]{ \frac{51}{2\pi}} \\ \\ r = 2.01 \\ \\ r = 2.0 cm](https://tex.z-dn.net/?f=34%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%5C%5C%2034%20%5Ctimes%203%20%3D%204%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%5C%5C%20102%20%3D%204%5Cpi%20%7Br%7D%5E%7B3%7D%20%20%5C%5C%20%20%7Br%7D%5E%7B3%7D%20%20%20%3D%20%5Cfrac%7B102%7D%7B4%7D%20%5Cpi%20%5C%5C%20%20%5C%5C%20r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B51%7D%7B2%5Cpi%7D%7D%20%20%5C%5C%20%20%5C%5C%20r%20%3D%202.01%20%5C%5C%20%20%5C%5C%20r%20%3D%202.0%20cm)
Diameter = 2 × 2cm
<h3>= 4cm</h3>
Hope this helps you
Mrs.Lombardo.<span>if you do the math out, 4/5 and 2/3 give you an LCD (Least Common Denominator) of 15, so this means 4/5 = 12/15, and 2/3 = 10/15. 4/5 is greater than 2/3. </span>
A nine can go into a 20 two whole times. After that, there's still
some room left in the 20, but it's only enough room for a 2.
